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olya-2409 [2.1K]
3 years ago
13

The cell membrane carryout the life function transport True False

Chemistry
2 answers:
murzikaleks [220]3 years ago
6 0

i am thinking it is true

jeyben [28]3 years ago
5 0
It will be the first one it is true
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Look at the following reaction. How could you increase the production of 2NH3(g)? N2(g) + 3H2(g) 2NH3(g) Increase the volume of
Zolol [24]
The correct option is B. To increase the production of ammonia, you have to increase the pressure of the system. Increase in pressure will result in increased production of ammonia because this will drive the chemical reaction forward.
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3 years ago
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Convert these temperatures to Celsius:<br><br> a. 303 K<br><br> d. 45 K
andre [41]

303K − 273.15 = 29.85°C

45K − 273.15 = -228.1°C

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2 years ago
What is the term for temperature in a room reaching the point where all exposed surfaces in room ignite?
eimsori [14]

Answer:flashover

Explanation: flashover are event that occurs when all of the combustible materials in a room reach their ignition temperatures at the same time

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3 years ago
What is the distance from earth to Neptune in standard notation and scientific notation.
ira [324]

Answer:

Scientific Notation: 4.45963 x 109 km (29.811 A.U.) Scientific Notation: 4.53687 x 109 km (30.327 A.U.) By Comparison: If you weigh 100 pounds on Earth, you would weigh 110 pounds on Neptune.

4 0
3 years ago
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Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1
kari74 [83]

Answer:

\boxed {\boxed {\sf 56 \ Joules}}

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

q=mc \Delta T

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C

q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)

Multiply the first numbers. The grams will cancel.

q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )

Multiply again. This time the degrees Celsius cancel.

q= 56 \ J

56 Joules of heat are needed.

4 0
3 years ago
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