T<span>he phenomenon of </span>static electricity<span> requires a separation of </span>positive<span> and </span>negative<span> charges. When two materials are in contact, electrons may move from one material to the other, which leaves an excess of </span>positive<span>charge on one material, and an equal </span>negative<span> charge on the other.</span>
Answer
given,
height of window = 4 m
time taken to travel = 1 s
acceleration due to gravity = 9.8 m/s²
u = -0.905 m/s
initial velocity of ledge v = 0
now,
v² = u² + 2 a s
(-0.905)² = 0 + 2 × 9.8 ×s
s = 0.042 m
Explanation:
(a) Hooke's law:
F = kx
7.50 N = k (0.0300 m)
k = 250 N/m
(b) Angular frequency:
ω = √(k/m)
ω = √((250 N/m) / (0.500 kg))
ω = 22.4 rad/s
Frequency:
f = ω / (2π)
f = 3.56 cycles/s
Period:
T = 1/f
T = 0.281 s
(c) EE = ½ kx²
EE = ½ (250 N/m) (0.0500 m)²
EE = 0.313 J
(d) A = 0.0500 m
(e) vmax = Aω
vmax = (0.0500 m) (22.4 rad/s)
vmax = 1.12 m/s
amax = Aω²
amax = (0.0500 m) (22.4 rad/s)²
amax = 25.0 m/s²
(f) x = A cos(ωt)
x = (0.0500 m) cos(22.4 rad/s × 0.500 s)
x = 0.00919 m
(g) v = dx/dt = -Aω sin(ωt)
v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)
v = -1.10 m/s
a = dv/dt = -Aω² cos(ωt)
a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)
a = -4.59 m/s²
Answer:
3 kg
Explanation:
Momentum before = momentum after
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
After jumping on the skateboard, the student and the skateboard have the same velocity, so v₁ = v₂.
m₁u₁ + m₂u₂ = (m₁ + m₂) v
(47.4 kg) (4.2 m/s) + m (0 m/s) = (47.4 kg + m) (3.95 m/s)
m = 3 kg
The kinetic energy of the diver as she hits the water is 159.72J. Details about kinetic energy can be found below.
<h3>How to calculate kinetic energy?</h3>
The kinetic energy of a body can be calculated using the following formula:
K.E = ½ × m × v²
Where;
- K.E = kinetic energy
- m = mass
- v = velocity
According to this question, a 66.0 kg diver is 2.30 m above the water and falls at speed of 2.20 m/s.
Kinetic energy = ½ × 66 × 2.2²
K.E = 159.72J
Therefore, the kinetic energy of the diver as she hits the water is 159.72J.
Learn more about kinetic energy at: brainly.com/question/12669551
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