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3 years ago

As the temperature of an object rises, so does the

Physics

2 answers:

FrozenT [24]3 years ago

5 0

Answer:

The correct answer Is C! Thermal energy of the object

Explanation:

nikklg [1K]3 years ago

3 0

C. The object is not in motion, ruling out A. We are not adding mass in any way, nor does adding heat to object increase its mass, therefore also ruling out B. Finally, we are not changing the object's position in such a way that gives it a higher ability to do work, ruling out D.

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If a car was moving at a speed of 25mph for 6 hours, how far would the car travel?

Anestetic [448]

Answer:

150 miles

Explanation:

25mph x 6hrs = 150miles

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3 years ago

What resistance is needed to cause a 20A current flow with a 100V battery?

timurjin [86]

Resistance = (voltage) / (current)

Resistance = (100 V) / (20 A)

Resistance = 5 Ω (D)

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3 years ago

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How are parentheses used in chemical formulas

Zarrin [17]

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4 years ago

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Aconstant current of 3 Afor 4 hours is required to charge an automotive battery. If the terminal voltage is V, where t is in hou

kirza4 [7]

Answer:

(a) 43.2 kC

(b) 0.012V kWh

(c) 0.108V cents

Explanation:

Given:

i = current flow = 3 A
t = time interval for which the current flow = $4\ h = 4\times 3600\ s = 14400\ s$
V = terminal voltage of the battery
R = rate of energy = 9 cents/kWh

Assume:

Q = charge transported as a result of charging
E = energy expended
C = cost of charging

Part (a):

We know that the charge flow rate is the electric current flow through a wire.

$\therefore i = \dfrac{Q}{t}\\\Rightarrow Q =it\\\Rightarrow Q = 3\times 14400\\\Rightarrow Q = 43200\ C\\\Rightarrow Q = 43.200\ kC\\$

Hence, 43.2 kC of charge is transported as a result of charging.

Part (b):

We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

$E = Vit\\\Rightarrow E = V\times 3\times 4\\\Rightarrow E = 12V\ Wh\\\Rightarrow E = 0.012V\ kWh\\$

Hence, 0.012V kWh is expended in charging the battery.

Part (c):

We know that the energy cost is equal to the product of energy expended and the rate of energy.

$\therefore \textrm{Cost}=\textrm{Energy}\times \textrm{Rate}\\\Rightarrow C = ER\\\Rightarrow C = 0.012V\times 9\\\Rightarrow C =0.108V\ cents$

Hence, 0.108V cents is the charging cost of the battery.

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4 years ago

Which of these statements about the sun's energy is true? (5 points)

s344n2d4d5 [400]

It is transferred evenly to water through air

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3 years ago