The distance travelled during the given time can be found out by using the equations of motion.
The distance traveled during the time interval is "13810.8 m".
First, we will find the deceleration of the motorcycle by using the first <em>equation of motion</em>:

where,
vi = initial velocity = (518 km/h)
= 143.89 m/s
vf = final veocity = 60 % of 143.89 m/s = (0.6)(143.89 m/s) = 86.33 m/s
a = deceleration = ?
t =time interval = 2 min = 120 s
Therefore,

a = -0.48 m/s²
Now, we will use the second <em>equation of motion </em>to find out the distance traveled (s):

<u>s = 13810.8 m = 13.81 km</u>
<u />
Learn more about the equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion.
Answer:
E=hf
Were, h = Planck constant 6.67*10^11
E=3.8*10^24 * 6.67*10^11= 2.508*q0^36j
Answer:
The transverse component of acceleration is 26.32
where as radial the component of acceleration is 8.77 
Explanation:
As per the given data
u=π/4 rad
ω=u'=2 rad/s
α=u''=4 rad/s

So the transverse component of acceleration are given as

Here


So

The transverse component of acceleration is 26.32 
The radial component is given as

Here

So

The radial component of acceleration is 8.77 
Answer:
i think the answer is constant
The two most common units of electric energy is Watts or hertz.