Answer:
k=320N/m
Explanation:
Step one:
given data
Let the initial/equilibrum position be x
mass m1= 0.2kg
F1= 0.2*10= 2N
elongation e= 9.5cm= 0.095m
mass m2=1kg
F2=1*10= 10N
elongation e= 12cm= 0.12m
Step two:
From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F
F=ke
2=k(0.095-a)
2=0.095k-ka----------1
10=k(0.12-a)
10=0.12k-ka----------2
solving equation 1 and 2 simultaneously
10=0.12k-ka----------2
- 2=0.095k-ka----------1
8=0.025k-0
divide both side by 0.025
k=8/0.025
k=320N/m
skin cancer and it cause to lost transportating process
Answer:C
Explanation:
Given
mass
is at
mark
mass
is at
mark
Scale is Pivoted at 
For scale to be in equilibrium net torque must be equal to zero
Taking ACW as positive thus


Therefore a net torque of 0.04 g is required in CW sense which a mass
can provide at a distance of
from pivot


therefore in meter stick it is at a distance of 
Peak value is what we say to the maximum value of the signal..
or rms value..root mean square value