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dmitriy555 [2]
3 years ago
10

If you mix 4.5 g of hcl in enough water to make 0.9 l (900 ml of solution, what is the molarity of the solution?

Chemistry
1 answer:
Elina [12.6K]3 years ago
4 0
We first need to convert grams of hydrogen chloride to moles.

molarity = moles of solute/liters of solution

To convert from grams to moles, we need to divide by it's molecular mass.

4.5 g HCl * (1 mole HCl/ 36.46 g HCl) = 0.123 moles HCl

0.12 moles/0.9 L = 0.13 M HCl

If they gave you the volume as 900 mL, then that would be 3 sig figs. And the sig figs would be limited to 2 because the mass.If, however, they gave you the volume as 0.9 L, then that would be 1 sig fig. And the final answer would be limited to to 1 sig fig.
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How many moles of each element are in this sample p2o3
iris [78.8K]

The sample P2O3 ia made P, phosphorus and oxygen elements.

One mole of P2O3 has 2 mole P and 3 mole O

Thus the molar ratio is 2:3


3 0
3 years ago
Investigate: Press Reset. Start with 2.000 moles of sulfur, then press Start. How many atoms do you think this amount represents
Scilla [17]

Answer:

1.204428 * 10^24 atoms

Explanation:

Number of moles = 2 mol

Number of atoms = ?

The relationship between moles and atoms is given by the avogadro's umber. This is the number of units in one mole of a substance.  The units can be atoms, ions etc In this case it is atoms. The number is equal to  6.02214076 * 10^23

This means;

1 mol = 6.02214076 * 10^23

2 mol = x

Upon solving for x,

x = 2 * 6.02214076 * 10^23

x = 12.04428 * 10^23

x = 1.204428 * 10^24 atoms

6 0
3 years ago
Assuming that the bath contains 250.0 g of water and that the calorimeter itself absorbs a negligible amount of heat, calculate
Anvisha [2.4K]

Answer:

-3272     kJ/mol

Explanation:

Given and known facts

Mass of Benzene = 0.187 grams

Mass of water = 250 grams

Standard heat capacity of water = 4.18 J/g∙°C

Change in temperature ΔT = 7.48°C

Heat

=250 * 4.18 * 7.48\\=7816.6 \\=7.82

Heat released by benzine is - 7.82 kJ

Now, we know that

0.187 grams of benzene release = -7.82  kJ heat

So, 1 g benzine releases

\frac{ -7.82 }{0.187}\\= -41.8

kJ/g

0.187 * \frac{1}{78.108}=0.00239 mol C6H6

Heat released

= \frac{-7.82}{ 0.00239}

=-3272     kJ/mol

4 0
3 years ago
I need help asap thank u
UNO [17]
It is b, i learned this last year hope this helps
4 0
3 years ago
"I think of a number, multiply it by itself and then add 6 to the result<br>+​
Sonja [21]

Answer:

ok 3 = 9 15 i got 15 so what

Explanation:

5 0
3 years ago
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