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3 years ago

If you mix 4.5 g of hcl in enough water to make 0.9 l (900 ml of solution, what is the molarity of the solution?

1 answer:

4 0

We first need to convert grams of hydrogen chloride to moles.

molarity = moles of solute/liters of solution

To convert from grams to moles, we need to divide by it's molecular mass.

4.5 g HCl * (1 mole HCl/ 36.46 g HCl) = 0.123 moles HCl

0.12 moles/0.9 L = 0.13 M HCl

If they gave you the volume as 900 mL, then that would be 3 sig figs. And the sig figs would be limited to 2 because the mass.If, however, they gave you the volume as 0.9 L, then that would be 1 sig fig. And the final answer would be limited to to 1 sig fig.

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ABOUT IT

MaRussiya [10]

Answer:

Molecules in the hot water bottle are

moving faster than molecules in the skin.

Explanation:

If the molecules in the skin were to be moving faster than the water then the water would seem to be cold.

5 0

2 years ago

The reduction of nitrogen monoxide is described by the following chemical equation: 2H2 (g) +2NO (g) 2H20 ()N2 (g Suppose a two-

Ipatiy [6.2K]

Answer:

Reasonable Second step- $N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)$

Explanation:

The given single step chemical reaction is as follows.

$2H_{2}(g)+2NO \rightarrow 2H_{2}O(g)+N_{2}(g)$

Suppose a two-step mechanism is proposed for this reaction,

The reaction occured in two steps they are as follows.

$Step -1:H_{2}(g)+2NO \rightarrow N_{2}O(g)+H_{2}O(g)$

$Step-2:N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)$

8 0

3 years ago

Aspirin (C9H8O4) is an acid which can be titrated with a base to determine purity. If an aspirin tablet weighing 0.615 g is titr

Iteru [2.4K]

Answer:

67.4 % of C₉H₈O₄

Explanation:

To make titrations problems we know, that in the endpoint:

mmoles of acid = mmoles of base

mmoles = M . volume so:

mmoles of acid = 20.52 mL . 0.1121 M

mmoles of acid = mg of acid / PM (mg /mmoles)

Let's determine the PM of aspirin:

12.017 g/m . 9 + 1.00078 g/m . 8 + 15.9994 g/m . 4 = 180.1568 mg/mmol

mass (mg) = (20.52 mL . 0.1121 M) . 180.1568 mg/mmol

mass (mg) = 414.4 mg

We convert the mass to g → 414.4 mg . 1g / 1000mg = 0.4144 g

We determine the % → (0.4144 g / 0.615 g) . 100 = 67.4 %

6 0

2 years ago

When 2.69 g 2.69 g of a nonelectrolyte solute is dissolved in water to make 345 mL 345 mL of solution at 26 °C, 26 °C, the solut

Gre4nikov [31]

Answer:

The molar concentration of this solution is 0.0463 mol/L

Explanation:

Step 1 : Data given

Mass of a nonelectrolyte solute = 2.69 grams

Volume of water = 345 mL = 0.345 L

Temperature = 26.0°CC = 273 + 26 = 299 K

The osmotic pressure = 863 torr

⇒ 863torr /760 = 1.13553 atm

Step 2: Calculate the molar concentration of this solution

Π = i*M*R*T

⇒with Π = the osmotic pressure = 1.13553 atm

⇒with i = the van't Hoff factor of the nonelectrolyte solute = 1

⇒with M = the molar concentration = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 299 K

1.13553 atm = 1 * M * 0.08206 L*atm/mol*K * 299 K

M = 1.13553 / (0.08206*299)

M = 0.0463 mol/L

The molar concentration of this solution is 0.0463 mol/L

5 0

2 years ago

List the properties of copper, sulfur and copper sulfide?

Y_Kistochka [10]

The answer would be metal

7 0

3 years ago