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Alekssandra [29.7K]

4 years ago

12

Zadania 1 Rowerzysta, poruszając się na rowerze ruchem jednostajnym prostoliniowym wykonał pracę 24 kJ. Jaką odległość pokonał r

owerzysta, jeżeli siła oporu ruchu wynosiła 30N? 1kJ = 1000J Zadanie 2 Oblicz pracę wykonaną przez ciało działające siłą 50N na drodze 20 cm. Zadanie 3 Spychając na pobocze zepsuty samochód, Stefan wykonał pracę 3000 J na drodze 6 m. Jaką siłą działał? Proszę o wysłanie w dniu dzisiejszym zadania 1,2,3.

1 answer:

Katyanochek1 [597]4 years ago

8 0

Answer:

Zadanie 1. Przebyty dystans wynosi 800 m

Zadanie 2. Wykonana praca to 10 J

Zadanie 3. Zastosowana siła wynosi 500 N.

Explanation:

Zadanie 1. Oto mamy;

Równanie wykonanej pracy, W = siła, F × odległość, D przesunięte w kierunku siły

Gdzie:

W = 24 kJ

F = 30 N.

D = wymagany

W związku z tym;

W = F × D daje nam;

24 kJ = 24000 J = 30 N × D

Stąd D = 24000 J / (30 N) = 800 J / N = 800 metrów

Zadanie 2. Wykonana praca, W = F × D

Tutaj;

F = 50 N.

D = 20 cm = 0,2 m

∴ W = 50 N × 0,2 m = 10 J

Wykonana praca = 10 J

Zadanie 3. Oto mamy

Z równania wykonanej pracy W;

W = F × D

Ponieważ W = 3000 J

D = 6 m

Dlatego 3000 J = F × 6 m

$F = \frac{3000 \, J}{6 \, m} = 500 \, N$

Siła = 500 N.

Moc jest podana w następującym równaniu

Moc = (praca wykonana) / (czas poświęcony na pracę).

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