Answer:
yes it could deform a shape or an object
Explanation:
An object moving with constant acceleration near the surface of the earth is influenced by the gravity. <span>In physics, </span>gravitational acceleration<span> is the </span>acceleration<span> on an object caused by the force of </span>gravitation<span>. Neglecting friction such as air resistance, all small bodies accelerate in a </span>gravitational <span>field at the same rate relative to the center of mass.</span>
A simple electromagnet consisting of a coil of insulated wire wrapped around an iron core<span>. A </span>core<span> of ferromagnetic material like </span>iron<span> serves to increase the magnetic field created. The strength of magnetic field </span>generated<span> is proportional to the amount of </span>current<span> through the winding.</span>
Answer:
![V = 228\ V](https://tex.z-dn.net/?f=V%20%3D%20228%5C%20V)
Explanation:
given,
charge of two spherical drop = 0.1 nC
potential at the surface = 300 V
two drops merge to form a single drop
potential at the surface of new drop = ?
![V = \dfrac{kq}{r}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7Bkq%7D%7Br%7D)
![r = \dfrac{9\times 10^9\times 0.1 \times 10^{-9}}{300}](https://tex.z-dn.net/?f=r%20%3D%20%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%200.1%20%5Ctimes%2010%5E%7B-9%7D%7D%7B300%7D)
r = 0.003 m
volume = ![2 \times \dfac{4}{3}\pi r^3](https://tex.z-dn.net/?f=2%20%5Ctimes%20%5Cdfac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
= ![2 \times \dfac{4}{3}\pi \times 0.003^3](https://tex.z-dn.net/?f=2%20%5Ctimes%20%5Cdfac%7B4%7D%7B3%7D%5Cpi%20%5Ctimes%200.003%5E3)
= 2.612 × 10⁻⁷ m³
![\dfac{4}{3}\pi R^3 = 2.612\times 10^{-7}](https://tex.z-dn.net/?f=%5Cdfac%7B4%7D%7B3%7D%5Cpi%20R%5E3%20%3D%202.612%5Ctimes%2010%5E%7B-7%7D%20)
R = 0.00396 m
![V = \dfrac{kq}{r}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7Bkq%7D%7Br%7D)
![V = \dfrac{9\times 10^9 \times 0.1 \times 10^{-9}}{0.00396}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B9%5Ctimes%2010%5E9%20%5Ctimes%200.1%20%5Ctimes%2010%5E%7B-9%7D%7D%7B0.00396%7D)
![V = 227.27](https://tex.z-dn.net/?f=V%20%3D%20227.27)
![V = 228\ V](https://tex.z-dn.net/?f=V%20%3D%20228%5C%20V)
Answer:
B = 32.17 x 10^-8 Tesla
u = 8.24 x 10^-8 J/m^3
P/A = 24.72 W/m^2
Explanation:
E = 96.5 V/m
velocity of light, c = 3 x 10^8 m/s
Let B be the magnetic field.
The relation between the electric field strength and the magnetic field strength is given by
B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla
Let u be the energy density.
![u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5Cvarepsilon%20_%7B0%7DE%5E%7B2%7D%2B%5Cfrac%7B1%7D%7B2%5Cmu%20_%7B0%7D%7DB%5E%7B2%7D)
![u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%208.854%5Ctimes%2010%5E%7B-12%7D%5Ctimes%2096.5%5Ctimes%2096.5%2B%5Cfrac%7B1%7D%7B2%5Ctimes%204%5Ctimes%203.14%5Ctimes%2010%5E%7B-7%7D%7D%5Ctimes%2032.17%5E%7B2%7D%5Ctimes%2010%5E%7B-16%7D)
u = 8.24 x 10^-8 J/m^3
Let Power flow per unit area is
P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2