Assuming that all energy of the small ball is transferred
to the bigger ball upon impact, then we can say that:
Potential Energy of the small ball = Kinetic Energy of
the bigger ball
Potential Energy = mass * gravity * height
Since the small ball start at 45 cm, then the height
covered during the swinging movement is only:
height = 50 cm – 45 cm = 5 cm = 0.05 m
Calculating for Potential Energy, PE:
PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J
Therefore, maximum kinetic energy of the bigger ball is:
<span>Max KE = PE = 0.98 J</span>
The horizontal is s or displacement
The vertical is t or time
Answer:
0.0327 m
Explanation:
m = 2 kg
ω = 24 rad/s
A = 0.040 m
Let at position y, the potential energy is twice the kinetic energy.
The potential energy is given by
U = 1/2 m x ω² x y²
The kinetic energy is given by
K = 1/2 m x ω² x (A² - y²)
Equate both the energies as according to the question
1/2 m x ω² x y² = 2 x 1/2 m x ω² x (A² - y²)
y² = 2 A² - 2 y²
3y² = 2A²
y² = 2/3 A²
y = 0.82 A = 0.82 x 0.040 = 0.0327 m
The speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.
<h3>
Speed of the satellite</h3>
v = √GM/r
where;
- M is mass of Earth
- G is universal gravitation constant
- r is distance from center of Earth = Radius of earth + 4930 km
v = √[(6.626 x 10⁻¹¹ x 5.97 x 10²⁴) / ((6371 + 4930) x 10³)]
v = 5,916.36 m/s
Thus, the speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.
Learn more about speed here: brainly.com/question/6504879
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