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Minchanka [31]
3 years ago
13

Is my. d.og c.u.te o.r wha.t?? quarantine scool checkk

Chemistry
2 answers:
garik1379 [7]3 years ago
7 0
Yes very cute bro bro
Murljashka [212]3 years ago
3 0

Answer:

yeah it's a little cute

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Wind : swirls :: chemical bond : ___________.
drek231 [11]
Options are as follow,

1)  Flashes
2)  Skips
3)  Stretches
<span>4)  Jumps
</span>
Answer:
            Option-3 (stretches) is the correct answer.

Explanation:
                    The best analogy which suits a chemical bond is the stretching of chemical bonds. Remaining verbs doesn't explain the property of chemical bond. For example, the chemical bonds did not flashes, neither they skip or jump.
                    The chemical bonds can stretch and bend. As predicted from IR spectroscopy, different bonds can stretch and bend at different energies. The stretching of bonds require more energy while, bending of bonds require less energy.
4 0
4 years ago
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PLEASE HELP BRAINLIEST AND 15 points.
PtichkaEL [24]

Answer:

Substance B, boiling point of 105 °C

Explanation:

Non volatile substances have high boiling points

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3 years ago
What is/are converted into carbon dioxide , water, and energy in aerobic respiration
Lana71 [14]

Cellular respiration involves breakdown of glucose into carbon dioxide and water in presence of oxygen, releasing energy. ... ATP molecule is converted into ADP molecule, whenever energy is needed for any metabolic reaction or activity. The energy stored in it is released to be used in metabolic reaction.

Hope this helps! So sorry if I'm wrong

3 0
3 years ago
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How much time would it take for 9000 atoms of nobellium-253 (half-life is 97 s) to decay to 2250 atoms?
Svetradugi [14.3K]

Answer:it’s 828292atoms

Explanation

7 0
3 years ago
I will mark brainlist please help
Lostsunrise [7]

Answer: 20) 2365 g

21) 22.39 grams.

22) 29.99 g

Explanation: 20) molarity is the no of moles of solute per unit volume.

We can calculate amount of CaCl2 required to prepare 0.1 M CaCl2 1000 ml solution.

we know that to prepare one ltr of 1 M solution of CaCl2 111 g required

Now consider x gram will require to prepare to

so that comparing above both condition

1000ml ×1M×X g=1000ml×0.1M×111g

X= 11.1 gram

X= 11.1 g of CaCl2

Hence 11.1 g of CaCl2 would be dissolved in 1.0L of a 0.100 M solution of CaCl2

21) How many moles of CaCl₂ in that solution?

;

;

.

What's the mass of that 0.20172 moles of CaCl₂?

Molar mass from a modern periodic table:

Ca- 40.078;

Cl- 35.45.

Molar mass of CaCl₂:

.

Mass of that 0.20172 moles of CaCl₂:

22) its a 3.0m solution so 1 litre of solution contains 3 moles of NaOH, 250ml of solution contains 0.25x39.9971 g/mol, so 250ml of this solution contains 0.75x39.9971=29.99g, or if you round it up 30.0g

7 0
3 years ago
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