mol=35:101.11 g/mol=0.346
formula units = 0.346 x 6.02 x 10²³ = 2.082 x 10²³
Flourine.
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Answer:
0.96g of sodium hydride
Explanation:
Equation of reaction:
NaH + H20 = NaOH + H2
Mass of hydrogen gas produced (m) = PVM/RT
P = 765torr - 28torr = 737torr = 737/760 = 0.97atm, V = 982mL = 982cm^3, M = 2g/mol, R = 82.057cm^3.atm/gmol.K, T = 28°C = 28 + 273K = 301K
m = (0.97×982×2)/(82.057×301) = 0.08g of hydrogen gas
From the equation of reaction
1 mole (24g) of sodium hydride produced 1 mole (2g) of hydrogen gas
0.08g of hydrogen gas would be produced by (24×0.08)/2 = 0.96g of sodium hydride
Answer:
Here you go! Hopefully this helps your question.
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Explanation:
None needed
Hello!
How many molecules are in 30 liters of methane (CH4) at STP ?
We have the following information:
Knowing that by Avogadro's Law for each mole of substance we have 6.02 * 10²³ molecules, it is known that in STP (Standard Temperature and Pressure) one mole of any gas equals 22.4 L, then:
22.4 L ----------------- 6.02*10²³ molecules
30 L -------------------- y molecules

multiply the means by the extremes




Answer:
8.0625*10²³ molecules of methane
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