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sukhopar [10]
3 years ago
10

_______ is a physical property

Chemistry
2 answers:
user100 [1]3 years ago
5 0

Answer:

C: Density

Explanation:

VMariaS [17]3 years ago
4 0

Answer:

C. Density

all the others are chemical properties

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Given 50g of sodium how many moles do you have? ​
Anastaziya [24]

Answer:

Amount of Na = 2.17moles

Explanation:

Mass of Na = 50g

Molar mass of Na = 23g/mol

Amount of mole = mass/molar mass

Amount of mole = 50/23

Amount of mole = 2.17moles

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4 years ago
Which word is the longest word in chemistry?​
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Isoleucine' is the chemical name of 'titin' (also known as 'connectin') - the largest known protein. It has 189,819 letters.
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3 years ago
If gas in a sealed container has a pressure of 50 kPa at 300 K, what will the pressure be if the temperature rises to 360 K?
VLD [36.1K]
The answer is 60 kpa, also did you try look it up because that is what i did but i did not copy and paste it. 

hope this helped have a good day
 
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3 years ago
Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
A 1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total
Strike441 [17]

Answer:

1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total volume of 33.0 mL, the osmotic pressure of the solution is 3.69 atm at 295 K.

5 0
3 years ago
Read 2 more answers
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