Company A has a sales position with a yearly salary of $42,000. Company B has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales.
Let x be the amount of yearly sales
Company A has a sales position with a yearly salary of $42,000.
yearly salary = 42,000
Company B has a similar sales position with a salary of $39,000 plus 1% commission on yearly sales.
1% is 0.01
yearly salary = 39,000+ 0.01x
yearly sales is the salary at company A greater than the salary and conmission at company B
A > B
42000 > 39000+ 0.01x
We solve the inequality
39000+ 0.01x < 42000
Subtract 39000 on both sides
0.01x < 3000
divide by 0.01
x> 300,000
For yearly sales > $300,000, the salary at company A greater than the salary and commission at company B
Answer:
Use by Prime factorisation method
Distance formula (See attachment below)
100 + 144
square root 244
15.620
Round to the nearest tenth
15.6
Answer:
$10,008.55
Add 10000, and 8.55 to give the total.
10,000.00
The cents will be .55 since the $10,000 does not have any cents included.
The $8 will stay since the $10,000 does not have any dollars below 10 dollars.
So, the answer will be $10,008.55
35 = 1/2h (6+1)
35 = 1/2 h + 7
28 = 1/2h
14 = 1h
14 = h
