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Nutka1998 [239]
3 years ago
10

The Doppler effect using ultrasonic waves of frequency 2.23×106 Hz is used to monitor the heartbeat of a fetus. A (maximum) beat

frequency of 258 Hz is observed. Part A Assuming that the speed of sound in tissue is 1.54×103m/s, calculate the maximum velocity of the surface of the beating heart.
Physics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

v = 8.89 cm/s

Explanation:

given,

frequency of ultrasonic wave = 2.23 x 10⁶ Hz

beat frequency = 258 Hz

speed of sound in the tissue =  1.54×10³ m/s

maximum velocity  = ?

using Doppler equation

f_1 = f_0 (\dfrac{c+ v}{c})..........(1)

f_2 = f_1 (\dfrac{c}{c-v})..........(2)

now, from equation (1) and (2)

f_2 = f_0 (\dfrac{c + v}{c-v})

f₂ = 2.23 x 10⁶ + 258 = 2230258 Hz

f₀ = 2.23 x 10⁶ Hz

c = 1540 m/s

2230258= 2230000(\dfrac{1540+ v}{1540-v})

1.00012(1540 - v ) = 1540+ v

1540.178 - 1.00012 v = 1540 + v

2.00012 v = 0.178

v = 0.08899 m/s

v = 8.89 cm/s

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Answer:

Explained

Explanation:

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8 0
2 years ago
A glass flask whose volume is 1000 cm^3 at a temperature of 1.00°C is completely filled with mercury at the same temperature. W
Marat540 [252]

Answer:

the coefficient of volume expansion of the glass is \mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

Explanation:

Given that:

Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³

temperature of the glass flask and mercury= 1.00° C

After heat is applied ; the final temperature = 52.00° C

Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C

Volume of the mercury overflow = 8.50 cm^3 = 8.50 ×  10⁻⁶ m³

the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K

The increase in the volume of the mercury =  10⁻³ m³ ×  51.00 × 1.80 × 10⁻⁴

The increase in the volume of the mercury = 9.18*10^{-6} \ m^3

Increase in volume of the glass =  10⁻³ × 51.00 × \beta _{glass}

Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask

the mercury overflow = (9.18*10^{-6}  -  51.00* \beta_{glass}*10^{-3})\ m^3

8.50*10^{-6} = (9.18*10^{-6}  -51.00* \beta_{glass}* 10^{-3} )\ m^3

8.50*10^{-6} - 9.18*10^{-6} = ( -51.00* \beta_{glass}* 10^{-3} )\ m^3

-6.8*10^{-7} =  ( -51.00* \beta_{glass}* 10^{-3} )\ m^3

6.8*10^{-7} =  ( 51.00* \beta_{glass}* 10^{-3} )\ m^3

\dfrac{6.8*10^{-7}}{51.00 * 10^{-3}}=  ( \beta_{glass} )

\mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

Thus; the coefficient of volume expansion of the glass is \mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

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2 years ago
What kind of radiation is emitted in the following nuclear reaction
miv72 [106K]

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So, the electrons are generally termed as beta particles while the positrons are termed as positive beta particles. So this is a kind of radioactive reactions where the reactant changes to new element by releasing an electron and thus there is a change in the atomic number of the product by one.

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I tryed to answer

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