Question

How many molecules are there in 6.07g of Ag2CO3

Answer 1

There are $1.3244 \times 10^{22}$ molecules in 6.07 grams of silver carbonate.

Explanation:

Moles of a compound is defined as ratio of mass of the compound to the molar mass of the compound.

• $Moles(n)=\frac{\text{Mass of the compound}(m)}{\text{Molar mass of the compound}(M)}$

1 mole corresponds to $N_A$ numbers of atoms or molecules or ions.

• 1 mole = $N_A$

$N_A$ = Avogadro number = $6.022 times 10^{23}$ atoms, molecules/ions

Number of molecules particles in 'n' moles of compound:N

• $N = n\times N_A$

Mass of silver carbonate,m = 6.07 g

Molar mass of carbonate ,M= 276 g/mol

Moles of silver carbonate = n

$n=\frac{m}{M}=\frac{6.07 g}{276 g/mol}=0.02199 mol$

Number of molecules of silver carbonate in 0.02199 moles.

$N=n\times N_A=0.02199 mol\times 6.022 times 10^{23}=1.3244 \times 10^{22} molecules$

There are $1.3244 \times 10^{22}$ molecules in 6.07 grams of silver carbonate.