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Tju [1.3M]
3 years ago
9

What are four functions for cells that are the same in all organisms

Chemistry
1 answer:
lukranit [14]3 years ago
3 0
Carbohydrates proteins nucleic acids and lipids
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Help needed ASAP, I will mark your answer as brainliest.
evablogger [386]

Answer:

b

Explanation:

b

4 0
3 years ago
Read 2 more answers
Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3
Goryan [66]

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Now put all the given values in the formula of molality, we get

0.038M=\frac{n}{0.278L}

n=0.0105mol  

mass of  Fe_2(SO_4)_3 = moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g

Thus 4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

3 0
3 years ago
For alpha decay to cause a loss in mass, such as that in the uranium 238 conversion to thorium 234, what must the atomic weight
Aleonysh [2.5K]

Explanation:

Reaction equation showing alpha decay in Uranium-238 is as follows.

    ^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He

It is known that an alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is ^{4}_{2}\alpha.

As atomic mass or weight is the sum of total number of protons and neutrons present in an atom.

Hence, the atomic weight of the alpha particle is (2 + 2) = 4.

6 0
3 years ago
Calculate the mass of water produced when 42 g of propane, c3h8, is burned with 115 g of oxygen
gavmur [86]
The balanced combustion reaction of propane, C₃H₈, is

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

Molar mass of propane: 44 g/mol
Moles of propane = 42 g * (1 mol/44g) = 0.9545 mol propane

Molar mass of oxygen: 32 g/mol
Moles of oxygen = 115 g * (1 mol/32 g) = 3.594 mol oxygen

Moles of oxygen needed to completely react propane:
0.9545 mol propane * (5 mol O₂/1 mol propane) = 4.7725 mol oxygen

Since the available oxygen is only 3.594 moles and propane needs 4.7725 moles, that means oxygen is our limiting reactant. We base the amount of water produced here.

Molar mass of water: 18 g/mol
Mass of water produced = 3.594 mol O₂ * (4 mol H₂O/5 mol O₂) * (18 g/mol)
Mass of water produced = 258.768 grams
6 0
3 years ago
What is the total of the amount of energy that is reflected back into space​
Tcecarenko [31]
Moon va half plus 22
7 0
3 years ago
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