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weqwewe [10]
3 years ago
7

The speed of a spaceship is going warp 7.58. What is the velocity of the spaceship in cm/min. Assume 1.00 warp = 2.5 times the s

peed of light
Speed of light= 2.9979x10^8 m/s
Chemistry
1 answer:
grandymaker [24]3 years ago
3 0

Answer : The velocity of the spaceship is, 3408.6\times 10^{10}cm/min

Solution :

As we are given that,

1.00\text{ wrap }=2.5\times \text{The speed of light}

The speed of a spaceship = 7.58 wraps

So, 7.58\text{ wrap }=7.58\times 2.5\times \text{The speed of light}

The speed of light = 2.9979\times 10^8m/s

Now put the value of speed of light in above expression, we get

So, 7.58\text{ wrap }=(7.58)\times (2.5)\times (2.9979\times 10^8m/s)=56.81\times 10^8m/s

The velocity of the spaceship = 56.81\times 10^8m/s

Now we have to convert the velocity of the spaceship m/s to cm/min.

Conversion :

(1 m = 100 cm)

(1 min = 60 sec)

The velocity of the spaceship = (56.81\times 10^8)\times 100\times 60cm/min=3408.6\times 10^{10}cm/min

Therefore, the velocity of the spaceship is, 3408.6\times 10^{10}cm/min

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Boyle’s Law illustrates the inverse relationship of volume and pressure. It follows the formula  p1V1 = P2V2 , where P1V1 denotes initial pressure and volume  and P2V2 denotes values of pressure and  volume.

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Consider the reaction of gaseous hydrogen with gaseous oxygen to produce gaseous water. Given that the first picture represents
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The question is incomplete. There's missing the image, which is shown below.

Answer:

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Explanation:

The reaction between hydrogen gas and oxygen gas to form water is:

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So, for 1 mol of O₂ is necessary 2 moles of H₂ form 2 moles of H₂O. As the images below there's 8 molecules of H₂, 4 molecules of O₂, 12 molecules in the mixture, and 8 molecules of H₂O. Thus, there are stoichiometric values.

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The number of moles and molecules are related, so let's substitute it in the equation. For the H₂:

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