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tigry1 [53]
3 years ago
10

Two ice skaters push off against one another starting from a stationary position. The 45.0-kg skater acquires a speed of 0.375 m

/s. What speed does the 60.0-kg skater acquire? Assume that any other unbalanced forces during the collision are negligible.
Chemistry
1 answer:
zalisa [80]3 years ago
6 0

Answer:

The speed of the 60.0 kg skater should be 0.281 m/s

Explanation:

<u>Step 1: </u>Data given

Mass of skater 1 = 45.0 kg

speed of skater 1 = 0.375 m/s

Mass of skater 2 = 60.0 kg

<u>Step 2:</u> Calculate the speed of skater 2

To solve this problem, we will use 'Conservation of momenton'. This means  the momentum before the push equals the momentum after.

momentum p = m*v

Momentum p(before) = momentum p(after)

m1*v1 = m2 * v2

⇒ with m1 = mass of skater 1 = 45.0 kg

⇒ with v1 = the velocity of skater 1 = 0.375 m/s

⇒ with m2 = the mass of skater 2 = 60.0 kg

⇒ with v2 = the velocity of skater 2 = TO BE DETERMINED

45.0 * 0.375 = 60.0 * v2

v2 = (45.0*0.375)/60

v2 = 0.281 m/s

The speed of the 60.0 kg skater should be 0.281 m/s

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A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to . He'll do this by add
erma4kov [3.2K]

Answer:

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Explanation:

It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:

" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "

Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.

To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂

Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.

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