Answer:
Explanation:
a ) For the ray going into syrup , angle of incidence ( i ) is 29.4 and angle of refraction ( r ) is 18.84
Refractive index of syrup = Sin i / Sin r
= Sin 29.4 / Sin 18.84
= 1.51 .
b ) The wavelength of a light is reduced in a medium by the factor of refractive index so
wavelength in the medium
= Wavelength in air / refractive index of the solution
= 632.8 / 1.51
= 419.07 nm .
The frequency remains unchanged . The frequency in the medium will be same as that in air or vacuum.
Frequency in air = Velocity of light in air / wavelength in light
= 3 x 10⁸ / 632.8 x 10⁻⁹
= 4.74 x 10¹⁴ Hz.
Frequency in the medium is same as that in air.
Velocity in the medium
V = velocity in air / refractive index
= 3 x 10⁸ / 1.51
= 1.98 x 10⁸ m /s
The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
Vertically,
s = 15.4 m
u = 0
a = 9.8 m / s²
15.4 = 0 + ( 1 / 2 * 9.8 * t² )
t² = 3.14
t = 1.77 s
Horizontally,
u = 3.01 m / s
a = 0 ( Since there is no external force )
s = ( 3.01 * 1.77 ) + 0
s = 5.34 m
Therefore, the distance travelled by the ball before hitting the ground is 5.34 m
To know more about distance travelled
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In 1920, after returning from Army service, he produced a successful model and in 1923 turned it over to the Northeast Electric Company of Rochester for development.
To solve this problem we will apply the concepts related to voltage as a dependent expression of the distance of the bodies, the Coulomb constant and the load of the bodies. In turn, we will apply the concepts related to energy conservation for which we can find the speed of this
Here,
k = Coulomb's constant
q = Charge
r = Distance to the center point between the charge
From each object the potential will be
Replacing the values we have that
Now the potential two is when there is a difference at the distance of 0.1 from the second charge and the first charge is 0.1 from the other charge, then,
Applying the energy conservation equations we will have that the kinetic energy is equal to the electric energy, that is to say
Here
m = mass
v = Velocity
q = Charge
V = Voltage
Rearranging to find the velocity
Replacing,
Therefore the speed final velocity of the electron when it is 10.0 cm from charge 1 is