H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
Answer:
The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.
When two point of a closed circuit is joined by a wire of zero resistance like if we connect the two terminals of cell by a wire of zero resistance then it is said that battery is short circuit.
similarly any two point of the circuit is said to be short circuit if the two points are connected by zero resistance wire.
so sudden large current will flow through the section which got short circuited
Answer:
Power= 6.84×10⁸ W
Explanation:
Given Data
Niagara falls at rate of=1.4×10⁶ kg/s
falls=49.8 m
To find
Power Generated
Solution
Regarding this problem
GPE (gravitational potential energy) declines each second is given from that you will find much the kinetic energy of the falling water is increasing each second.
So power can be found by follow
Power= dE/dt = d/dt (mgh)
Power= gh dm/dt
Power= 1.4×10⁶ kg/s × 9.81 m/s² × 49.8 m
Power= 6.84×10⁸ W
Answer:
5 Days to Seconds = 432000
Explanation: