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Maru [420]
3 years ago
11

What net force is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/secondÆ? (Assume a f

lat, frictionless surface.)
A. 6.1 Newtons
B. 59 Newtons
C. 5.8 x 10^2 newtons
D. 6.0 x 10^2 newtons
Physics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0
We Know, F = m*a
Here, m = 59 Kg
a = 9.75 m/s²

Substitute their values in the expression, 
F = 59*9.75
F = 575.25 Kg.m/s²

So, your final answer is 575.25 N

Hope this helps!
Marizza181 [45]3 years ago
7 0

Answer : F=5.8\times 10^2\ Newtons amount of force is required to push a sofa.

Explanation :

It is given that,

The mass of sofa, m = 59 kg

Acceleration, a=9.75\ m/s^2

According to Newton's second law of motion :

F = ma

m is the mass and a is the acceleration produced.

F=59\ kg\times 9.75\ m/s^2

F = 575.25 Newtons

F=5.75\times 10^2\ Newtons

or

F=5.8\times 10^2\ Newtons

Hence, this is the required solution.

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Answer:

2.65m/s

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Given

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v² = 6.9972

v=√6.9972

v = 2.65m/s

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5 0
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Ulleksa [173]
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A soccer player icks a rock horizontally off a 40m high cliff into a pool f water if the player hears the sound of the splash s
Semenov [28]

Answer:

v = 9.936 m/s

Explanation:

given,

height of cliff = 40 m

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assuming that time to reach the sound to the player = 3 s

now,

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t = \sqrt{\dfrac{2s}{g}}

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d =28.387 m

v x 2.875=28.387 m

v = 9.936 m/s

7 0
3 years ago
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