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2 years ago

Which best explains why water has a much higher boiling point than would otherwise be predicted?

Chemistry

2 answers:

My name is Ann [436]2 years ago

7 0

Answer: water from strong hydrogen bonds

Explanation:

ikadub [295]2 years ago

5 0

My guess is that water is a liquid and not a solid, or a gas. It can be heated by us or by the suns rays, which if done by the suns rays the water azorbs the light rising the temp to the point of boil which then makes the water evaporate into the air, and thus making cloud in the sky that we see all the time thus when the clouds become big enough it begins to rain. ( also called the water cycle)

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A 19.0 g piece of metal is heated to 99.0 °C and then placed in 150 mL of water at 21°C. The temperature of the water rose to 23

Anna35 [415]

Answer:

$0.8696\ \text{J/g}^{\circ}\text{C}$

Explanation:

$m_m$ = Mass of metal = 19 g

$c_m$ = Specific heat of the metal

$\Delta T_m$ = Temperature difference of the metal = $99-23=76^{\circ}\text{C}$

V = Volume of water = 150 mL = $150\ \text{cm}^3$

$\rho$ = Density of water = $1\ \text{g/cm}^3$

$c_w$ = Specific heat of the water = 4.186 J/g°C

$\Delta T_w$ = Temperature difference of the water = $23-21=2^{\circ}\text{C}$

Mass of water

$m_w= \rho V\\\Rightarrow m_w=1\times 150\\\Rightarrow m_w=150\ \text{g}$

Heat lost will be equal to the heat gained so we get

$m_mc_m\Delta T_m=m_wc_w\Delta T_w\\\Rightarrow c_m=\dfrac{m_wc_w\Delta T_w}{m_m\Delta T_m}\\\Rightarrow c_m=\dfrac{150\times 4.186\times 2}{19\times 76}\\\Rightarrow c_m=0.8696\ \text{J/g}^{\circ}\text{C}$

The specific heat of the metal is $0.8696\ \text{J/g}^{\circ}\text{C}$ .

4 0

2 years ago

Is/are determined by a genetic trait passed on from parents to their children

Darya [45]

Answer:genes

Explanation:

7 0

2 years ago

What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen? 2C6H6(g) 15O2(g) mc001-1. Jpg 12CO2(g) 6H2O

Andrei [34K]

The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .

The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.

The thermochemical equation for the combustion of benzene is;

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol

We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.

Learn more: brainly.com/question/13164491

8 0

1 year ago

Use the iupac nomenclature rules to give the name for this compound - n2o3.

wel

By use IUPAC nomenclature rule compound N2O3 is named as

Dinitrogen trioxide ( answer d)

Nitrogen (N2) is named before oxygen(O3) since they are arranged alphabetically. In addition the prefix Di is used infront of nitrogen since they are two nitrogen atoms while prefix tri is used infront of oxide since they are 3 oxygen atoms

8 0

2 years ago

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Mr. McPhillip has a ribbon of magnesium (Mg), a silvery metal. As a demonstration for his class, he sets the metal on fire. It b

OLEGan [10]

A. Magnesium is an element and after it is burned it is a compound

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2 years ago

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