Answer:
3m/s²
Explanation:
Force applied to an object can be calculated thus;
F = ma
Where;
F = force applied (Newtons)
m = mass of substance (kg)
a = acceleration (m/s²)
According to the information provided in this question, F = 12.0 newtons, m = 4.0 kg, a = ?
Derived from F = m.a
We have; a = F/m
a = 12/4
a = 3
The resultant acceleration of the object is 3m/s².
Freezing point depression depends of the number of particles of the solute in the solution.
1)Pure water have highest freezing point. All other solutions with given solutes will have lower temperatures.
2) The more particles of the solute in the solution the lower freezing point is going to be.
<span>b. 1.0 m NaCl ( dissociates and give 2 mol ions (1 mol Na⁺ and 1 mol Cl⁻))
c. 1.0 m K3PO4 (</span>dissociates and give 4 mol ions (3 mol K⁺ and 1 mol PO4³⁻)<span>
d. 1.0 m CaCl2 (</span>dissociates and give 3 mol ions (1 mol Ca²⁺ and 2 mol Cl⁻))<span>
e. 1.0 m glucose (c6h12o6) (glucose does not dissociate, and solution have
1 mole of particles of the solute(glucose))
The largest number of particles has </span>1.0 m K3PO4 solution, and it is has lowest freezing point . Answer is C.
Answer:
I screenshot and expained here
https://screenshot.best/A7QIKV.lnk
Explanation:
- See charge on ion is -1 .
Hence it has taken 1 electron
Now first look at EC of Fluorine(F)
- Now one electron added .hence no of electrons is 10now
Look at the EC
Or
![\\ \bull\sf\dashrightarrow [He]](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Csf%5Cdashrightarrow%20%5BHe%5D)
Option C is correct.
