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zysi [14]
3 years ago
10

Cubic centimeter is a unit used to measure A) mass B) area C) weight D) volume

Chemistry
2 answers:
Shalnov [3]3 years ago
5 0
The answer to this is volume.
Oksanka [162]3 years ago
3 0
That would be volume D
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One litre of hydrogen at STP weight 0.09gm of 2 litre of gas at STP weight 2.880gm. Calculate the vapour density and molecular w
expeople1 [14]

Answer:

we know, at STP ( standard temperature and pressure).

we know, volume of 1 mole of gas = 22.4L

weight of 1 Litre of hydrogen gas = 0.09g

so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.

similarly,

weight of 2L of a gas = 2.88gm

so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g

hence, molecular weight of the gas = 32.256g

vapor density = molecular weight/2

= 32.256/2 = 16.128g

hence, vapor density of the gas is 16.128g.

Explanation:

4 0
3 years ago
Hhhhhheeeeeellllllppppp me ffffaaaßstttt ananaanaanswswwwwweeeerrrr
LenKa [72]

Answer:

Diseases of Poultry
a. ESCHERICHIA COLI INFECTIONS.
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Explanation:

3 0
3 years ago
Read 2 more answers
Unknown # 41
sveta [45]

Answer:

KI

Explanation:

From the question, we can see that a qualitative analysis of the compound shows that it has a lilac flame colour. The lilac flame colour corresponds to the potassium ion (K^+).

Again, the test of addition of HNO3(aq) and AgNO3(aq) to a solution is a test for halogens. If the result is a green precipitate, then the ion present is the iodide ion (I^-).

Hence, the compound must be KI.

4 0
3 years ago
Assume that acid rain has lowered the ph of a particular lake to ph 5.0. what is the hydroxide ion concentration of this lake?
Ray Of Light [21]

That acid rain has lowered the ph of a particular lake to ph 5.0. the hydroxide ion concentration of this lake is

1 × 10^-9 mol of hydroxide ions per liter of lake water

 pH  +  pOH  =  14

 pOH  =  14  - 5

 pOH  =  9.00

 pOH  =  -log [OH⁻]

[OH⁻]  =  10^-pOH

[OH⁻]  = 10^{-9} mol

Therefore,

the hydroxide ion concentration of this lake is 1 × 10^-9 mol

To learn more about Concentration

brainly.com/question/10725862

#SPJ4

5 0
2 years ago
Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus
alex41 [277]

Answer: 35.4 g

Explanation:

The balanced reaction is :

2P+3Cl_2\rightarrow 2PCl_3

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of phosphorous}=\frac{15.5g}{31g/mol}=0.50moles

\text{Moles of phosphorous chloride}=\frac{50.9g}{137g/mol}=0.372moles

2P+3Cl_2\rightarrow 2PCl_3

According to stoichiometry :

2 moles of phosphorous chloride are produced by = 3 moles of Cl_2

Thus 0.37 moles of phosphorous chloride are produced by=\frac{3}{2}\times 0.372=0.558moles of Cl_2

Mass of Cl_2=moles\times {\text {Molar mass}}=0.558moles\times 71g/mol=35.4g

Thus 35.4 g of chlorine reacted with the phosphorus

5 0
3 years ago
Read 2 more answers
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