What is the percentage of s-character in an sp hybrid? O 25% 50% o 75% O 66%

Chemistry

1 answer:

marishachu [46]2 years ago

8 0

Answer: 50%

Explanation:

The number of electron pairs are 2 for hybridization to be $sp$ and the electronic geometry of the molecule will be linear.

1. percentage of s character in sp hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{2}\times 100=50\%$

2. percentage of s character in $sp^2$ hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{3}\times 100=33.3\%$

3. percentage of s character in $sp^3$ hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{4}\times 100=25\%$

Thus percentage of s-character in an sp hybrid is 50%.

You might be interested in

Which organism would have the most variation in the DNA of its offspring?

Arada [10]

The organism that would have the most variation in the DNA of its offspring is the cat (Option C). Meiosis is a type of cell division that generates more genetic variability than asexual types of reproduction.

Meiosis is a type of reductional cell division by which a parental cell produces 4 daughter cells (gametes), each containing half of the genetic material.

Animals (e.g., cats) generate gametes by meiosis which fuse during fertilization to produce new offspring.

Both amoeba and bacteria reproduce by a type of asexual reproduction called binary fission. Moreover, yeasts also reproduce asexually by a process called budding and fission.

Both asexual and sexual types of reproduction generate genetic variability by the emergence of new mutations in daughter cells.

Meiosis generates much more genetic variability than asexual types of reproduction due to two different processes:

Random assortment of chromosomes, which produces new allele combinations.

Recombination, i.e., by the exchange of genetic material (DNA) between non-sister chromatids during Prophase I.

Learn more in:

brainly.com/question/7002092

5 0

2 years ago

Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcy

Shtirlitz [24]

Answer:

5-chloro-2-methylcyclohexanol

Explanation:

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. In this case, the priority functional group is the alcohol group, so we will start the counting of the carbons in this group. Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, in this case, we can assign the number 2 to the methyl group and 5 to the chloride group, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.

Since the other options involve: high countings for the susbtituents groups (3-chloro-6-methylcyclohexanol), wrong assignation of priority functional group (1-chloro-4-methylcyclohexanol), wrong sequence of counting in the compound (2-methyl-3-chlorocyclohexanol) and no alphabetical order to name the compound (2-methyl-5-chlorocyclohexanol), the correct option is:

5-chloro-2-methylcyclohexanol

Have a nice day!

4 0

3 years ago

You heat 3.869 g of a mixture of fe3o4 and feo to form 4.141 g fe2o3. What is the mass of oxygen reacted?

Lostsunrise [7]

The reaction is

FeO + Fe3O4 + 1/2 O2---> 2Fe2O3

Thus as shown in the balanced equation two moles of Fe2O3 are formed when 0.5 moles of O2 reacted with mixture of FeO and Fe3O4

moles of Fe2O3 = MAss / Molar mass = 4.141 / 159.69 = 0.0259 moles

So moles of O2 needed = 0.5 X 0.0259 = 0.01295

Mass of O2 = moles X molar mass = 0.01295 X 32 = 0.4144 grams