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Bingel [31]
3 years ago
11

How many grams of acetylene react if 1.10 mil of CO2 are produced

Chemistry
1 answer:
Tems11 [23]3 years ago
5 0
The combustion reaction of acetylene has a balanced equation
C2H2+3O2--->2H2O+2CO2
Using the ratio 1:3:2:2, if 1.10 mols of CO2 are produced, assuming complete combustion, than that means that 0.55 mols of acetylene (C2H2) must have been combusted. The molar mass of acetylene is 26, so the answer is 26*0.55 = 14.3 grams
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Which must be a mixture of substances?<br> (1) solid (3) gas<br> (2) liquid (4) solution
brilliants [131]
Answer=4

A solution is a mixture of substances
4 0
3 years ago
In a chemical reaction, which are the most likely products of these reactants 4Fe+302
Cerrena [4.2K]

2Fe2O3, reason is when we add 4Fe + 3O2, we get the same answer, but in a different form.

8 0
4 years ago
Consider the following equilibrium:
Ainat [17]

<u>Answer: </u>The equation which is wrong is K_p=K_c(RT)^{-5}

<u>Explanation:</u>

For the given reaction:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

The expression for K_c\text{ and }K_p is given by:

K_c=\frac{1}{[O_2]^3}

K_p=\frac{1}{[O_2]^3}

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between K_p\text{ and }K_c is given by the expression:

K_p=K_c\times (RT)^{\Delta n_g}

where,

\Delta n_g= number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

\Delta n_g = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for K_p is:

K_p=K_c\times (RT)^{-3}

Therefore, the equation which is wrong is K_p=K_c(RT)^{-5}

7 0
4 years ago
How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm
Ierofanga [76]
Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

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3 0
3 years ago
A small hole in the wing of a space shuttle requires a 20.7-cm² patch.
cricket20 [7]

The Patch's area of the space shuttle in km² is 2.07 × 10⁻⁹ km²

Given, that a space shuttle requires a 20.7 cm² patch

We have to convert the patch's area from cm² into km².

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

Patch area of the space shuttle is 20.7 cm²

1 cm = 0.00001 km

or, 1 cm² = (0.00001 km)²

or,  1 cm² = 10⁻¹⁰km²

20.7 cm² = 20.7 ×  10⁻¹⁰km²

20.7 cm² = 2.07 × 10⁻⁹ km²

The patch area in square kilometers is 2.07 × 10⁻⁹ km²

To learn more about unit conversion, visit: brainly.com/question/11543684

#SPJ4

8 0
2 years ago
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