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Zigmanuir [339]
3 years ago
7

Fruit Baskets

Mathematics
1 answer:
ivolga24 [154]3 years ago
7 0

Answer:

2.22

2.03

2.21

Step-by-step explanation:

6.65 divided by a total of 3lb = 2.22 (rounded up from 2.21666667)

10.15 divided by a total of 5lb = 2.03

17.70 divided by a total of 8lb = 2.21 (rounded down from 2.2125)

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$125 you will end up w/ $5125

Step-by-step explanation:

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In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (
DENIUS [597]

Answer:

  • a) T is not homogeneous
  • b) T is not additive
  • c) T is not homogeneous
  • d) T is not additive
  • e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

  • a) T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0). These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).
  • b) T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5). Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).
  • c) T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0) so T is not homogeneous.
  • d) T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0) then T is not additive.
  • e) T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0) then T is not additive.
8 0
3 years ago
Can someone help me please
Furkat [3]

Answer:

answer for question 7. 0.17×70 = $11.9

8 0
3 years ago
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