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Anni [7]
3 years ago
12

An atom has a mass number of 22 and an atomic number of 12. How many neutrons does it have?

Chemistry
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

this isn't correct answer but the equation is correct by using this methid you can got your answer .

Explanation:

Given - Mass number of atom = 23

                                Atomic number of atom = 11

As, no. of electrons in an atom is equal to an atomic number of the element.

So, number of electrons = 11

Secondly , number of protons are equal to number of electrons.

so, number of protons = 11

And number of neutrons = mass number - atomic number = 23−11 = 12

so, number of neutrons = 12

So , the atom contains 11 protons, 11 electrons, 12 neutrons.

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When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t
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Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

Mn(s)+2HCl(aq)\rightarrow  MnCl_2(aq)+H_2(g)

Mass of solution = m

Volume of solution = 100.0 mL

Density of solution = d = 1.00 g/mL

m=1.00 g/mL\times 100.0 mL = 100 g

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{final} = final temperature = 23.1^oC

T_{initial} = initial temperature = 28.9^oC

Now put all the given values in the above formula, we get:

q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

q=2,242.4 J=2.242 kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = \frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol

\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

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