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lys-0071 [83]
3 years ago
13

Does a car have antennae? what senses does it have

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Explained below.

Explanation:

Yes cars have antennas.

Now there could be an antenna for listening to radio stations which could be regular radio stations or even satellite radio stations.

Also, there could be antennas used for GPS navigation or some form of communication with other vehicles that possess that type of antenna.

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Depends, but generally, it does not include the day the order was placed.
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A positive symptom of schizophrenia would be
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Answer:

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Explanation:

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3 years ago
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Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the app
Aleks04 [339]

The angle of baking from the calculation is obtained as 30°.

<h3>What is banking?</h3>

The term banking refers to a means of preventing vehicles from skidding off the road at curves.

We know that the banking angle is obtained from;

θ = tan-1(v^2/rg)

v = 24.5 m/s

r = 110 m

g = 9.8 m/s^2

θ = tan-1(25^2/9.8 * 110)

θ = tan-1(625 /1078)

θ = 30°

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8 0
2 years ago
A 2150 kg satellite used in a cellular telephone network is in a circular orbit at a height of 780 km above the surface of the e
Tom [10]

Answer:

a)F=16741.9N

b)\frac{F}{W}=0.795

Explanation:

The gravitational force on the satellite is calculated with Newton's Gravitation Law:

F=\frac{GMm}{r^2}

Where M=5.97\times10^{24}kg is Earth's mass, m=2150kg is the satellite mass, r=R+h is the distance between their centers, where h=780000m is the height of the satellite (from Earth's surface) and R=6371000m is Earth's radius, and G=6.67\times10^{-11}Nm^2/kg^2 is the gravitational constant.

a) With these values we then have:

F=\frac{GMm}{r^2}=\frac{(6.67\times10^{-11}Nm^2/kg^2)(5.97\times10^{24}kg)(2150kg)}{(6371000m+780000m)^2}=16741.9N

b) And the fraction this force is of the satellite’s weight <em>W=mg</em> is:

\frac{F}{W}=\frac{GMm}{mgr^2}=\frac{GM}{gr^2}=\frac{(6.67\times10^{-11}Nm^2/kg^2)(5.97\times10^{24}kg)}{(9.8m/s^2)(6371000m+780000m)^2}=0.795

5 0
4 years ago
A piano wire with mass 3.00 g and length 80.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and ampli
lys-0071 [83]

Answer:

(a) P_{avg} = 0.22 W

(b) P_{avg,2} = 0.056 W

Explanation:

given information:

the mass of piano wire, m = 3.00 g = 0.003 kg

tension, F = 25 N

length, l = 80 cm = 0.8 m

frequency, f = 120 Hz

amplitude, A = 1.6 mm = 0.0016 m

(a) the average power carried by the wave, P_{avg}

P_{avg} = \frac{1}{2}(√μF)ω²A²

where,

ω = 2πf = 2π120 = 754s^{-1}

μ = \frac{m}{l}

  = \frac{0.003}{0.8}

  = 0.00375 kg/m

thus,

P_{avg} = \frac{1}{2}(√(0.00375)(25))(754)²(0.0016)²

P_{avg} = 0.22 W

(b) What happens to the average power if the wave amplitude is halved.

based on the equation above, we know that the average power is proportional to the square amplitude. therefore

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{A_{2} ^{2} } }

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{(0.5A_{1} )^{2} } }

P_{avg,2} = \frac{0.22}{4}

P_{avg,2} = 0.056 W

4 0
3 years ago
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