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3 years ago

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The temperatureTdin degrees Fahrenheit in terms of the Celsius temperaturedis given by=Td+9/5d+32.The temperatureCvin degrees Ce

lsius in terms of the Kelvin temperaturevis given by=Cv−v273.Write a formula for the temperatureFvin degrees Fahrenheit in terms of the Kelvin temperaturev.It is not necessary to simplify.

1 answer:

Shalnov [3]3 years ago

7 0

Answer:

$T_F=\frac{9}{5}(T_K-273)+32$

Explanation:

Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula $T_F=\frac{9}{5}T_C+32$ and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula $T_C=T_K-273$ , we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining $T_F=\frac{9}{5}(T_K-273)+32$ .

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Answer with Step-by -step explanation:

We are given that

b. $\mid A\mid=46 m$

$\theta=20^{\circ}$ below the positive x-axis

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y-Component of vector A= $A_y=\mid A\mid sinx=46sin340=46(-0.34)=-15.64$

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y-Component of vector B= $B_y=86sin42=57.62$

Vector A= $A_xi+A_yj=43.24i-15.64j$

Vector B= $B_xi+B_yj=63.64i+57.62j$

Vector C=A+B

Substitute the values

$C=43.24i-15.64j+63.64i+57.62j$

$C=106.88i+41.98j$

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The direction of the vector C=21.5 degree

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A coil has 400 turns and self-inductance 7.50 mH. The current in the coil varies with time according to i = 1680 mA2 cos [πt/(0.

zhannawk [14.2K]

Answer:

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(b) 0.0126 Wb

(c) 0.0493 V

Solution:

As per the question:

No. of turns in the coil, N = 400 turns

Self Inductance of the coil, L = 7.50 mH = $7.50\times 10^{- 3}\ H$

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$e = e_{o}sin{\pi t}{0.0250}$

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