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arlik [135]
3 years ago
14

The temperatureTdin degrees Fahrenheit in terms of the Celsius temperaturedis given by=Td+9/5d+32.The temperatureCvin degrees Ce

lsius in terms of the Kelvin temperaturevis given by=Cv−v273.Write a formula for the temperatureFvin degrees Fahrenheit in terms of the Kelvin temperaturev.It is not necessary to simplify.
Physics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

T_F=\frac{9}{5}(T_K-273)+32

Explanation:

Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula T_F=\frac{9}{5}T_C+32 and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula T_C=T_K-273, we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining T_F=\frac{9}{5}(T_K-273)+32.

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Two cars are traveling along a straight line in the same direction, the lead car at 25 m/s and the other car at 35 m/s. At the m
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Answer:

a. t_1=12.5\ s

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Explanation:

Given:

  • speed of leading car, u_1=25\ m.s^{-1}
  • speed of lagging car, u_{2}=35\ m.s^{-1}
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a.

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v_1=u_1+a_1.t_1

where:

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t_1= time taken

0=25-2\times t_1

t_1=12.5\ s

b.

using the eq. of motion for the given condition:

v_2^2=u_2^2+2.a_2.\Delta s

where:

v_2= final velocity of the chasing car after braking = 0

a_2= acceleration of the chasing car after braking

0^2=35^2+2\times a_2\times 45

a_2=-13.61\ m.s^{-2} must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c.

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0=35-13.61\times t_2

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