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3 years ago

Where is the magnetic field of a bar magnet the strongest?

1 answer:

4 0

The correct answer is A. The magnetic field is strongest at the north pole and the south pole of a bar magnet. At the poles, the magnetic field is equally strong while the force is weaker at the middle of the bar. The field lines are closely packed at each pole and it gets wider as the lines get further from the pole.

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An analytical chemist is titrating of a solution of propionic acid with a solution of . The of propionic acid is . Calculate the

motikmotik

Answer:

Heres my attempt at this and hope it helps friend

.1372L * (.83M/L) = .114 mols propanoic acid

.06862L * (1.1M/L) = 0.0755 mols NaOH

using the henderson hasselbach equation

ph = pKa + log([A-]/[HA])

ph = 4.89 + log(.0755/.114) = 4.72

Explanation:

Identify at least three reasons the Articles of Confederations failed as a governing document. In your opinion, evaluate which defect was most debilitating, using evidence and your knowledge of American government to justify your position.

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3 years ago

The combustion of 0.25 mol of an unknown organic compound results in the release of 320 kJ of energy. Which of the compounds in

vichka [17]

Answer: C. ethanol

The enthalpy of combustion is the amount of heat produced when one mole of ethanol undergoes complete combustion at 25 ° C and 1 atmosphere pressure, yielding products also at 25 ° C and 1 atm.

The enthalpy of combustion of the unknown compound is

ΔH = - 320 kJ / 0.25 mol = - 1280 kJ / mol

To choose a probable compound according to this combustion enthalpy, we must evaluate the deviation in relation to the values reported in the literature for the three probable compounds (methane, ethylene and ethanol). The deviation (e%) will be calculated according to the following equation,

e% = ( | ΔHx - ΔH | / ΔHx ) x 100%

where ΔHx is the enthalpy of combustion of the probable compound.

The following table shows the combustion enthalpies of the probable compounds and their deviation in relation to the enthalpy of ΔH = - 1280 kJ / mol

Compound Enthalpy of combustion (kJ/mol) Deviation

Methane - 890.7 43.8%

Ehylene -1411.2 9.3%

Ethanol -1368.6 6.5%

According to the previous table, we can say that the most probable compound is ethanol, since it has the smallest deviation in relation to the experimental enthalpy value of combustion.

5 0

3 years ago

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Name two methods scientists use to obtain empirical evidence

adell [148]

Through hypothesis and experiments

4 0

3 years ago

The equilibrium concentrations of the reactants and products are [ HA ] = 0.260 M [HA]=0.260 M , [ H + ] = 2.00 × 10 − 4 M [H+]=

ValentinkaMS [17]

Answer:

pKa of the acid HA with given equilibrium concentrations is 6.8

Explanation:

The dissolution reaction is:

HA ⇔ H⁺ + A⁻

So at equilibrium, Ka is calculated as below

Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260

= 15.38 x 10⁻⁸

Hence, by definition,

pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813

7 0

3 years ago

Zac releases the air from a balloon. Which statement best describes what will happen to the air that was inside the balloon?

ad-work [718]

The correct answer is the last option. When Zac releases the air from a balloon, it will expand to fill the room. It will not expand in the sense that molecules will be big but the molecules will be more spread out into the room and more air molecules will be present to fill the room.

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3 years ago

Read 2 more answers