Answer:
1.18 × 10⁷ c
Iron is the anode and zinc is the cathode.
Explanation:
Let's consider the reduction of Zn²⁺.
Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
<em>How many coulombs of charge are needed to produce 61.2 mol of solid zinc?</em>
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We can establish the following relations:
- When 2 moles of electrons circulate, 1 mol of Zn is produced.
- 1 mole of electrons have a charge of 96468 c (Faraday's constant).
Then, for 61.2 mol of Zn:
<em>Identify the anode and cathode when plating an iron nail with zinc.</em>
The anode is where the oxidation takes place and the cathode is where the reduction takes place.
Anode (oxidation): Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻
Cathode (reduction): Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
Answer:
H30,+ion is known as Hydroniom Ion
Explanation:
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Answer:
C- an explanation as to why you chose your topic
Explanation:
Answer:
240g
Explanation:
Using the equation m=pV, where m=mass, p=density, and V=Volume
m=(6)(40)=240
m=240
Lead chromate is a precipitate that is formed on the reaction of lead nitrate with sodium chromate. The best method to separate this precipitate from the solution is filtration.
- A precipitate can be defined as an insoluble solid formed in a chemical reaction. It appears as a cloudy and resulted after a reaction.
- The lead chromate is yellow colored precipitate that forms after the reaction of lead nitrate with sodium chromate.
- The process of separation of insoluble solids from the liquids by the use of filters is known as filtration. Insoluble solids are also called as precipitates these precipitates are formed in a chemical reaction.
- Filtration will help in separation of insoluble solid yellow colored lead chromate precipitate from the solution using a porous material or filter that selectively inhibits the passage of solid precipitate material and allows the solution to pass through it.
Learn more about filtration:
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