A position-time graph is shown below:
1 answer:
Answer: The object moves forward at 5 m/s, stops, and then changes velocity.
Explanation:
With the information given in the question we can graph the points (image attached).
As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.
Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.
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Answer:
10573375000
Explanation:
k = Coulomb constant =
r = Distance =
E = Electric field = 1150 N/C
Electric field is given by
Number of electrons is given by
Number of excess electrons is 10573375000
r = 0.115+0.15 = 0.265 m
The electric field is
Answer:
1250
Explanation:
Let's look at this in a simple manner, because it is.
The crane weights 250Kg. Okay.
Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)
Since F = m * a
F = 250 * 10
F = 2500
Now we know that the downward Force is 2500N.
To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be .
Therefore, the force pulling the box in the cable's direction is:
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