Please explain in more detail
<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.
<u>Explanation:</u>
The equation for the deposition of Ga(s) from Ga(III) solution follows:

- To calculate the total charge, we use the equation:

where,
C = charge
I = current = 0.490 A
t = time required (in seconds) =
(Conversion factor: 1 min = 60 s)
Putting values in above equation, we get:

- To calculate the moles of electrons, we use the equation:

where,
C = charge = 147 C
F = Faradays constant = 96500

- Now, to calculate the moles of gallium, we use the equation:

where,
n = number of electrons transferred = 3
Putting values in above equation, we get:

- To calculate the mass of gallium, we use the equation:

Moles of Gallium = 
Molar mass of Gallium = 69.72 g/mol
Putting values in above equation, we get:

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.
Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg
Answer:
I think it would be C or D
Explanation:
I'm sorry I couldn't give you the correct answer, but glad I was able to try and help you. Have a blessed day!