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3 years ago

13

Consider the electric force between a pair of charged particles a certain distance apart. By Coulomb's Law: If instead, the char

ge of both particles is doubled, the force is _____.
a. unchanged
b. halved
c. doubled
d. quadrupled

1 answer:

Westkost [7]3 years ago

5 0

Answer:

the answer is d

Explanation:

from F=Q1Q2

r².

then wen both charges are doubled

F=2Q1 ×2Q2

r²

F=4Q1Q2

r²

then 4 has to be the factor multiplied by the other part of the equation for it to balance

4F=4Q1Q2

r²

so theoretically the 4 on the LHS can cancel the 4 on the RHS

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A single-turn current loop carrying a 4.00 A current, is in the shape of a right-angle triangle with sides of 50.0 cm, 120 cm, a

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We need to calculate the angle β

Using cosine law

$50^2=130^2+120^2-2\times130\times120\cos\beta$

$\cos\beta=\dfrac{50^2-130^2-120^2}{2\times130\times120}$

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The direction of force is out of page.

We need to calculate the force on 50 cm side

Using formula of force

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Hence, The magnitude of the magnetic force on each of the three sides of the loop are 0 N, 0.1385 N and 0.1385 N.

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