Answer:
k = 4,92x10⁻³
Explanation:
For the reaction:
AB₂C (g) ⇄ B₂(g) + AC(g)
The equilibrium constant, k is defined as:
![k = \frac{[B_{2}][AC]}{[AB_2C]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5BB_%7B2%7D%5D%5BAC%5D%7D%7B%5BAB_2C%5D%7D)
<em>(1)</em>
Molar concentration of the species are:
[AB₂C]: 0,0840mol / 5L = <em>0,0168M</em>
[B₂]: 0,0350mol / 5L = <em>0,0070M</em>
[AC]: 0,0590mol / 5L = <em>0,0118M</em>
Replacing this values in (1):
![k = \frac{[0,0070][0,0118]}{[0,0168]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5B0%2C0070%5D%5B0%2C0118%5D%7D%7B%5B0%2C0168%5D%7D)
<em>k = 4,92x10⁻³</em>
I hope it helps!
I think it's letter:
B.Coefficients are placed in front of the reactants and/or products
68 kg. There are 58 kg salt in 500 gal seawater.
<em>Step 1.</em> Convert gallons to litres
1 US gal = 3.79 L (1 Imp gal = 4.55 L)
<em>Step 2</em>. Find the volume of the seawater
Volume = 500 gal × (3.79 L/1 gal) = 1895 L
<em>Step 3</em>. Find the mass of the seawater
Mass = 1895 L × (1.025 kg/1 L) = 1942 kg
<em>Step 4</em>. Find the mass of the salt
Mass of salt = 1942 kg seawater × (3.5 kg salt/100 kg seawater) = 68 kg salt
Answer:
This bubbled-up magma is cooled by frigid seawater to form igneous rock. This rock (basalt) becomes a new part of Earth's crust. Seafloor spreading occurs along mid-ocean ridges—large mountain ranges rising from the ocean floor.
Explanation:
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Answer:
2.52 atm
Explanation:
Change C to K.
Solve for P1=P2V2T2/V1T1
- Hope that helps! Please let me know if you need further explanation.
