How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?
2 answers:
Answer: The correct answer is 16 ohms.
Explanation:
The mathematical expression from Ohm's law is as follows;
V=IR
Here, I is the current, V is the potential and R is the resistance.
It is given in the problem that the potential in the circuit is 240 V and the current is 15 A.
Calculate the resistance by rearranging the above expression.
Put I= 15 A and V= 240 V.
R= 16 ohms
Therefore, the value of the resistance is 16 ohms.
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Answer:
so rate constant is 4.00 x 10^-4
Explanation:
Given data
first-order reactions
85% of a sample
changes to propene t = 79.0 min
to find out
rate constant
solution
we know that
first order reaction are
ln [A]/[A]0 = -kt
here [A]0 = 1 and (85%) = 0.85 has change to propene
so that [A] = 1 - 0.85 = 0.15.
that why
[A] / [A]0= 0.15 / 1
[A] / [A]0 = 0.15
here t = (79) × (60s/min) = 4740 s
so
k = - {ln[A]/[A]0} / t
k = -ln 0.15 / 4740
k = 4.00 x 10^-4
so rate constant is 4.00 x 10^-4