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mixer [17]
3 years ago
7

How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?

Physics
2 answers:
Mkey [24]3 years ago
8 0
THE ANSWER IS 16 ohms or however its spelled
alex41 [277]3 years ago
7 0

Answer: The correct answer is 16 ohms.

Explanation:

The mathematical expression from Ohm's law is as follows;

V=IR

Here, I is the current, V is the potential and R is the resistance.

It is given in the problem that the potential in the circuit is 240 V and the current is 15 A.

Calculate the resistance by rearranging the above expression.

R=\frac{V}{I}

Put I= 15 A and V= 240 V.

R=\frac{240}{15}

R= 16 ohms

Therefore, the value of the resistance is 16 ohms.

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Does gravity have an effect on the potential difference of a battery?
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Answer: The correct answer is "No".

Explanation:

Gravity: It is the force which causes object to fall on the earth. It is the force which attracts bodies towards each other.

Potential difference: It is defined as the potential acting between the two points. The work done in moving the unit positive charge from one location to the another location.

The potential difference in battery is caused by the electrodes. There are two terminals in battery: Negative terminal which is at lower potential and Positive terminal which is at higher potential. It forces the electrons to flow in the circuit which constitutes the current.

The gravity and the potential difference have no relation between them.

Therefore, gravity have no effect on the potential difference of a battery.

5 0
3 years ago
An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4 000 miles). At this location,
Taya2010 [7]

Answer:0.25 times

Explanation:

Given

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Force on the satellite is F=mg'

where g'=acceleration due to gravity at that point

Distance from center of Earth=R+R=2R

Gravitational Force is given by

F=\frac{GM_1M_2}{r^2}

Force F=mg'=\frac{GMm}{4R^2}-----1

Force on earth surface F=mg=\frac{GMm}{R^2}------2

Divide 1 and 2 we get

\frac{g'}{g}=\frac{R^2}{4R^2}

g'=\frac{g}{4}  

7 0
3 years ago
A toy rocket fires its engines to launch it straight up from rest. After a short time, the engine turns off and the
madreJ [45]

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at 10 seconds.. b/c that's when the velocity stops increasing..

Explanation:

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serg [7]
I would say B. hope it helps 
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