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sammy [17]
3 years ago
6

Light is an electromagnetic wave and travels at the speed of 3.00 x 10^8 m/s

Physics
1 answer:
Over [174]3 years ago
6 0
I think the answer is 2 hope it helps
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A boy jogs 250 meters in 110s what is the average speed
Artyom0805 [142]
The rule to get the average speed is as follows:
average speed = average distance / average time

We are given that:
distance = 250 m
time = 110 sec

Substitute with the givens in the above equation to get the average speed as follows:
average speed = 250/110 = 25/11 meters/sec
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2 years ago
How do the meetings of the words exercise and fitness differ?
ICE Princess25 [194]
Exercise is the activity and fitness is a lifestyle and done with time
7 0
2 years ago
What type of music classes would you lime to see next year?
Alexus [3.1K]

Answer:

If I were you, I would recommend a trumpet its the easiest instrument to play butits my opinion its your decision.

Explanation:

8 0
2 years ago
Which quantities appear in the equation for the magnetic field component of an electromagnetic wave?
tankabanditka [31]

Answer:

The speed of light (c)

Explanation:

The equation that relates the magnetic field component of an electromagnetic wave the the electric field component of the wave is:

E=cB

where

E is the magnitude of the electric field component

B is the magnitude of the magnetic field component

c is the speed of light in a vacuum, whose value is

c=3.0 \cdot 10^8 m/s

Re-arranging the equation to solve for B, we find:

B=\frac{E}{c}

5 0
2 years ago
While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th
Dovator [93]

Answer:

Explanation:

From the given information:

radius = 15 m

Time T = 23 s

a) Speed (v) = \dfrac{2 \pi r}{T}

v = \dfrac{2\times \pi \times 15}{23}

v = 4.10 m/s

b) The magnitude of the acceleration is:

a = \dfrac{v^2}{r} \\ \\ a = \dfrac{(4.10)^2}{15}

a = 1.12 m/s²

c) True weight = mg

Apparent weight = normal force

From the top;

the normal force = upward direction,

weight is downward as well as the acceleration.

true weight - normal force = ma  

apparent weight =mg - ma  

\dfrac{apparent \ weight}{true \  weight} = \dfrac{(mg - ma)}{(mg)}

=1- \dfrac{1.12}{9.8}

= 0.886 m/s²

d)

From the bottom;

acceleration is upward, so:

apparent weight - true weight = ma

apparent weight = true weight + ma

\dfrac{apparent \ weight }{true \ weight} =\dfrac{ mg + ma}{mg}

\dfrac{apparent \ weight }{true \ weight} =1+ \dfrac{a}{g} \\ \\ = 1 + \dfrac{1.12}{9.8}

= 1 + \dfrac{1.12}{9.8} \\ \\

= 1.114 m/s²

6 0
3 years ago
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