204 ft = 62.2 m
We know that the initial velocity of the rocket was 0, we can find its acceleration using:
s = ut + 1/2 at²
62.2 = 0.5a(6)²
a = 3.46 m/s²
Now, the final velocity of the rocket:
v = u + at
v = 3.46 x 6
v = 20.76 m/s = 68.1 ft/s
Answer:
M=125 kg
v=1.75 m/s
Explanation:
From the law of linear momentum
P =mv
Case 1 50*V =M* 0.7 equation 1
50*V =(M+50)* 0.5 equation 2
equating 1 and 2
M* 0.7=(m+50)* 0.5
0.2 M= 25
M=125 kg
Putting value of M in equation 1
50*V =125*0.7
V=1.75 m/s
Answer:
R=V/I=6/2=3ohm
time =5minutes =5*60=300seconds
I=2A
Heat =I^2Rt=(2)^2*3*300=4*900=3600J