How far does Outerspace go? What does it smell like?

Chemistry

2 answers:

tankabanditka [31]3 years ago

6 0

Answer:

A long time ago in a question far far away, it asked what does space smell like. Well... today is you're lucky day, because i happen to know what space smells like. It smells like NOTHING! :-)

Explanation:

But... fr, space actually smells according to Astronauts returning from space. They claim that their suits smell burnt. The lingering scent of space is “acrid” and “metallic,” like a charred meat or welding fumes.

And according to Google, the universe goes on for about 46.5 billion light-years. Oof, thats a long way! :-O

Hope this answers your questions, :-)

fiasKO [112]3 years ago

4 0

Answer:

billions and billions of miles away

And it smells like chicken

Explanation:

but for real you can't smell up there or you'll like die because you cannot breath in outer space lol

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Anastaziya [24]

Answer:

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3 years ago

In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?

Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, $Au$ atoms in $KAu(CN)_2$ = $6.66\times 10^{20}$ atoms (given)

From the formula of compound that is $KAu(CN)_2$ it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, $K$ atoms in $KAu(CN)_2$ = $6.66\times 10^{20}$ atoms

Number of carbon, $C$ atoms in $KAu(CN)_2$ = $2\times6.66\times 10^{20}$ atoms = $13.32\times 10^{20}$

Number of nitrogen, $N$ atoms in $KAu(CN)_2$ = $2\times6.66\times 10^{20}$ atoms = $13.32\times 10^{20}$

Total number of atoms in $KAu(CN)_2$ = Number of gold, $Au$ atoms+Number of potassium, $K$ atoms +Number of carbon, $C$ atoms + Number of nitrogen, $N$ atoms

Total number of atoms in $KAu(CN)_2$ = $6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}$