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Iteru [2.4K]
4 years ago
8

What is the name of the scientist who discovered the electron

Chemistry
1 answer:
Anastaziya [24]4 years ago
7 0
I think its J.J Thomson
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A soft drink contains 12.1% sucrose (C12H22O11) by mass. What volume of the soft drink solution in milliliters contains 102.5 g
galina1969 [7]

The volume of the soft drink solution in milliliters that contains 102.5 g of sucrose is 11.93mL.

<h3>How to calculate volume?</h3>

The volume of a solution can be calculated by dividing the mass by the density. That is;

Volume = mass/density

According to this question, a soft drink contains 12.1% sucrose (C12H22O11) by mass. This means that the mass of the sucrose is

12.1/100 × 102.5 = 12.40g of sucrose

Volume = 12.40g ÷ 1.04g/mL

Volume = 11.93mL

Therefore, the volume of the soft drink solution in milliliters that contains 102.5 g of sucrose is 11.93mL.

Learn more about volume at: brainly.com/question/1578538

4 0
2 years ago
What is a neutron and what charge does it have
Gnoma [55]
It’s a polyatomic and it has a negative charge. It’s located in the nucleus of the atom, along with the protons.
5 0
4 years ago
Read 2 more answers
What two chemical elements make up the majority of our sun
Vsevolod [243]
The two  chemical elements that make up the <span>majority of our sun is :
"Hydrogen" and "Helium"

Hope this helps!</span>
8 0
3 years ago
Read 2 more answers
Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K
Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-

And the undergoing chemical reaction:

MgCl_2+2NaF\rightarrow MgF_2+2NaCl

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2

Next, the moles of magnesium chloride consumed by the sodium fluoride:

n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M

[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M

Thereby, the reaction quotient is:

Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0
3 years ago
When you take 10 grams of salt, and dissolve it in 25 grams of hot water what is the solubility
AURORKA [14]

Answer:

When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules. ... Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together.

Explanation:

4 0
2 years ago
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