The pickle's centripetal acceleration is 0.03125 m/s²
<h3>Further explanation</h3>
Centripetal Acceleration can be formulated as follows:
<em>a = Centripetal Acceleration ( m/s² )</em>
<em>v = Tangential Speed of Particle ( m/s )</em>
<em>R = Radius of Circular Motion ( m )</em>
Centripetal Force can be formulated as follows:
<em>F = Centripetal Force ( m/s² )</em>
<em>m = mass of Particle ( kg )</em>
<em>v = Tangential Speed of Particle ( m/s )</em>
<em>R = Radius of Circular Motion ( m )</em>
Let us now tackle the problem !
<em>To find the pickle's centripetal acceleration can be carried out in the following way:</em>
<u>Given:</u>
Radius of Circular Motion = 0.08 m
Tangential Speed of Pickle = 0.05 m/s
<u>Unknown:</u>
Centripetal Acceleration of Pickle = a = ?
<u>Solution:</u>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Circular Motion
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant