The new volume : 21.85 ml
<h3>Further explanation</h3>
Given
V1=25,0 ml
P1=725 mmHg
T1=298K is converted to
T2=273'K
P2=760 mmHg atm
Required
V2
Solution
Combined gas law :
Input the value :
V2=(P1.V1.T2)/(P2.T1)
V2=(725 x 25 ml x 273)/(760 x 298)
V2=21.85 ml
Answer:
what kind of class u in like dam
Explanation:
A. M x L = moles.
<span>b. CH3COOH + NaOH ==> CH3COONa + H2O </span>
<span>I...6 mmols....0.......7.5 mmoles </span>
<span>C... 0........0.51 mmols..0 </span>
<span>E...6-0.511 ....0.......7.5+0.511 </span>
<span>I stands for initial </span>
<span>C stands for change. </span>
<span>E stands for equilibrium. </span>
<span>Just divide mmoles by 1000 to convert to moles. I work in mmoles because I get tired of writing those zeros. </span>
<span>c. done as in b.</span>
•3.9g of ammonia
•molar mass of ammonia = 17.03g/mol
1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:
(3.9 g)/ (17.03g/mol) = 0.22900763mols
Then convert the moles to molecules by multiplying it with Avogadro’s number:
Avogadro’s number: 6.022 x 10^23
0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules
