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2 years ago

Based on what you know about matter explain why the food coloring mixes at different rates

Chemistry

1 answer:

emmasim [6.3K]2 years ago

3 0

Answer:

Matter has different densities. Different food colorings have different densities. Those with a higher density will sink to the bottom and mix much easier than one with a lower density. The higher density also contains more particles making it easier to mix or give it a fuller color.

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Sevin, the commercial name for an insecticide used to protect crops such as cotton, vegetables, and fruit, is made from carbamic

xeze [42]

Answer:

Explanation:

Ratio of mass of C , N , H and O

= .8007 :0.9333:0.2016:2.133

Ratio of moles of C , N , H and O

= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16

= .0667 : .0667: .2016 : .1333

= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667

= 1 : 1 : 3: 2

Hence empirical formula = CNH₃O₂

7 .

Weight of titanium Ti = 1.916 g

Weight of oxygen = 3.196 - 1.916 = 1.28 g

Ratio of weight of Ti and O

= 1.916 : 1.28

Ratio of moles of Ti and O

1.916/48 : 1.28/16 [ Molecular weight of Titanium is 48 ]

= .04 : .08

= .04/.04 : .08/.04

= 1 :2 .

Empirical formula

TiO₂

5 0

3 years ago

Which of these are ionic compounds? Check all that apply.

SIZIF [17.4K]

I think the correct answers from the choices listed above are the first, third and the last option. Ionic compounds are compounds that dissociates into ions when in aqueous solution. From the list, NH4Cl, KF and MgO are the ionic compounds. Hope this answers the question.

5 0

3 years ago

Read 2 more answers

In a 1.0× 10–6 M solution of Ba(OH)2(aq) at 25 °C, identify the relative molar amounts of these species.

Marysya12 [62]

Thank you for posting your question here. Below is the solution:

HNO3 --> H+ + NO3-
HNO3 = strong acid so 100% dissociation 
** one doesn't need to find the molarity of water since it is the solvent 

0M HNO3 
1x10^-6M H3O+ 
1x10^-6M NO3- 
1x10^-8M OH-.....the Kw = 1x10^-14 = [H+][OH-] 
you have 1x10^-6M H+ so, 1x10^-14 / 1x10^-6 = 1x10^-8M OH- 

1x10^-6 Ba(OH)2 = strong base, 100% dissociation 
1x10^-6M Ba2+ 
2x10^-6M OH- since there are 2 OH- / 1 Ba2+ 
0M Ba(OH)2 
5x10^-9M H3O+

4 0

3 years ago

Determine the total mass of water formed when 22.67g of NH3 reacts.

Valentin [98]

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5 0

3 years ago

A slurry of flakes soybeans weighing a total of 100 kg contains 75 kg of inert solids and 25 kg of solution with 10 wt% oil and

lubasha [3.4K]

Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

C= solvent(oil)

$F_{solution}$ = mass of solvent + mass of oil (i.e A+C)

Feed Phase:

Total feed (i.e slurry of flakes soybeans)= 100kg

B= mass of solid =75 kg

F= mass of solvent + mass of oil (i.e A+C)

= 25kg

Mass ratio of oil to solution $Y_{F}$ = $\frac{Mass C}{Mass (A+C)}$

mass of oil (C) =25 × 0.1 wt = 2.5kg

mass of hexane in feed = 25 × 0.9 =22.5kg + 2.5 =25kg

therefore $Y_{F}$ = $\frac{2.5}{25}$

= 0.1

mass ratio of solid to solution $Y_{A}$ = $\frac{Mass A}{Mass (A+C)}=[tex]\frac{75}{25}$

Solvent Phase:

C= Mass of oil= 0(kg)

A= Mass of hexane = 100kg

mass of solutions = A+C = 0+100kg

solvent= 100kg

Underflow:

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

the value of N for the outlet and underflow is 1.5 kg

i.e N₁ = $\frac{mass B}{mass(A+C)}$

solution in underflow E₁ = Mass (A+C)

Overflow:

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75= E₁ × N₁

75 = E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

5 0

3 years ago