The electrical panel schedules are located on EWR Plan number __

What statement exemplifies the role of archeology in architecture?

horrorfan [7]

The answer is B because an architect designs buildings

5 0

2 years ago

if a current of 5 amps flows through a resistance of 40 ohms, what is the voltage across that resistor

olasank [31]

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

7 0

2 years ago

Savabuck University has installed standard pressure-operated flush valves on their water closets. When flushing, these valves de

Dvinal [7]

Answer:

Cost = $2527.2 per month.

Explanation:

Given that

Discharge ,Q = 130 L/min

So

$Q=0.13\ m^3/min$

Cost = $0.45 per cubic meter

1 month = 30 days

1 days = 24 hr = 24 x 60 min

1 month = 30 x 24 x 60 min

1 month = 43,200 min

Lets x $m^3\ water\ waste\ in\ a\ month$

x = 0.13 x 43,200

$x=5616\ m^3$

So the total cost = 5616 x 045 $

Cost = $2527.2 per month.

7 0

3 years ago

Rsidential Solar Solution:a. A type of photovoltaic solar panel manufactured in China receives a rating of 250W. The rating proc

aksik [14]

Answer:

a) $\eta = 13.455\%$ , b) $E_{day} = 812.716\,kJ$ , c) $C_{month. total} = 19.505\, USD$ , d) $t = 40.588\,years$

Explanation:

a) The area of the solar panel is:

$A = (20\,ft^{2})\cdot (\frac{0.3048\,m}{1\,ft} )^{2}$

$A = 1.858\,m^{2}$

The energy potential is determined herein:

$\dot E_{o} = (1000\,\frac{W}{m^{2}} )\cdot (1.858\,m^{2})$

$\dot E_{o} = 1858\,W$

The efficiency of the solar panel is:

$\eta = \frac{\dot E}{\dot E_{o}}\times 100\%$

$\eta = \frac{250\,W}{1858\,W}\times 100\%$

$\eta = 13.455\%$

b) The energy generated by the solar panel is presented below:

$E_{day} = (0.135)\cdot (150\,\frac{W}{m^{2}} )\cdot (20\,ft^{2})\cdot \left(\frac{0.3048\,m}{1\,ft} \right)^{2}\cdot (6\,h)\cdot (\frac{3600\,s}{1\,h} )\cdot (\frac{1\,kJ}{1000\,J} )$

$E_{day} = 812.716\,kJ$

c) The energy generated per month and per panel is:

$E_{month} = 30\cdot E_{day}$

$E_{month} = 30 \cdot (812.716\,kJ)\cdot \left(\frac{1\,kWh}{3600\,kJ} \right)$

$E_{month} = 6.773\,kWh$

Monthly energy savings due to the use of 18 panels are:

$C_{month, total} = 18\cdot E_{month}\cdot c$

$C_{month, total} = 18\cdot (6.773\,kWh)\cdot (\frac{0.16\,USD}{1\,kWh} )$

$C_{month. total} = 19.505\, USD$

d) The payback of the solar energy system is:

$t = \frac{9500\,USD}{12\cdot (19.505\,USD)}$

$t = 40.588\,years$

6 0

3 years ago

A Carnot cycle is to be designed to attain

Anni [7]

Answer:

reservoir is 727°C, then low temperature

Explanation:

Efficiency for any Heat engine = Work done by engine / Heat provided to the engine

Also, for a carnot engine derived formula for Carnot Engine

= 1- T2/T1

Where, T2 = sink reservoir temperature

and T1 = source reservoir temperature

727° C = 1000 K

So, 0.75 = 1-T2 / 1000

So, T2 = 1000*0.25 = 250 K = -23 Kelvin

8 0

3 years ago

The electrical panel schedules are located on EWR Plan number ___.