I don't know how to anwser this but and gas hybrid uses and gas powered motor so tiny explosions inside of the cyiliders but the electric car uses and electric motor powered by a simple battery...I still don't know if this is correct....
Answer:
Power, P = 722.96 watts
Explanation:
It is given that,
Voltage, V = 120 V
Length of nichrome wire, l = 8.9 m
Diameter of wire, d = 0.86 mm
Radius of wire, r = 0.43 mm = 0.00043 m
Resistivity of wire, ![\rho=1.3\times 10^{-6}\ \Omega-m](https://tex.z-dn.net/?f=%5Crho%3D1.3%5Ctimes%2010%5E%7B-6%7D%5C%20%5COmega-m)
We need to find the power drawn by this heater. Power is given by :
![P=\dfrac{V^2}{R}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BV%5E2%7D%7BR%7D)
And, ![R=\rho\dfrac{l}{A}](https://tex.z-dn.net/?f=R%3D%5Crho%5Cdfrac%7Bl%7D%7BA%7D)
![P=\dfrac{V^2\times A}{\rho\times l}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BV%5E2%5Ctimes%20A%7D%7B%5Crho%5Ctimes%20l%7D)
![P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B120%5E2%5Ctimes%20%5Cpi%20%280.00043%29%5E2%7D%7B1.3%5Ctimes%2010%5E%7B-6%7D%5Ctimes%208.9%7D)
P = 722.96 watts
So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.
Answer:
The number of calories needed is 6c.
Explanation:
The amount of energy
needed to raise the temperature
of water of mass
is
![Q = mC\Delta T](https://tex.z-dn.net/?f=Q%20%3D%20mC%5CDelta%20T)
where
is the specific heat capacity of water.
Putting in numbers into equation (1), we get:
![Q = (2g)(1)(3^oC )\\](https://tex.z-dn.net/?f=Q%20%3D%20%282g%29%281%29%283%5EoC%20%29%5C%5C)
![\boxed{Q = 6\:cal }](https://tex.z-dn.net/?f=%5Cboxed%7BQ%20%3D%206%5C%3Acal%20%7D)
which is the number of calories needed.
Answer:
The solution is given in the picture attached below
Explanation:
Answer:
The current decreases.
Explanation:
Current and resistance are inversely proportional. The equation connecting current, resistance and voltage is
, where V is voltage, I is current and R is resistance.
Rearranging this equation, you get:
and
![R = \frac{V}{I}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7BV%7D%7BI%7D)
If the value of voltage in both equations remains constant, and the value of R decreases, the value of I will increase. Conversely, if in the second equation
, the value of V remains constant the value of I decreases, then the value of R, resistance will increase.
Thus, it can be seen that the current will decrease as resistance increases and vice versa.