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olganol [36]
3 years ago
13

a cannon sits on a stationary railroad flatcar with a total mass of 1000 kg. when a 10 kg cannonball is fired to the left at a s

peed of 50 m/s, what is the speed of the flatcar
Physics
1 answer:
marishachu [46]3 years ago
6 0

Answer:

0.5 m/s

Explanation:

From Newton's Third law of motion,

Momentum of the cannon = momentum of the flatcar.

mv = MV........................ Equation 1

Where m = mass of the cannon, v = velocity of the cannon, M = mass of the flatcar, V = Velocity of the flat car.

make V the subject of the equation

V = mv/M................... Equation 2

Given: m = 10 kg, v = 50 m/s, M = 1000 kg

Substitute into equation 2

V = 10×50/1000

V = 500/1000

V = 0.5 m/s

Hence the speed of the flatcar = 0.5 m/s

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Answer:

La motocicleta recorre 25 metros en 1 segundo si circula a una velocidad de 90 km/h

Explanation:

La velocidad es una magnitud que expresa el desplazamiento que realiza un objeto en una unidad determinada de tiempo, esto es, relaciona el cambio de posición (o desplazamiento) con el tiempo.

Siendo la velocidad es el espacio recorrido en un período de tiempo determinado, entonces 90 km/h indica que en 1 hora la motocicleta recorre 90 km. Entonces, siendo 1 h= 3600 segundos (1 h=60 minutos y 1 minuto=60 segundos) podes aplicar la siguiente regla de tres: si en 3600 segundos (1 hora) la motocicleta recorre 90 km, entonces en 1 segundo ¿cuánta distancia recorrerá?

distancia=\frac{1 segundo*90 km}{3600 segundos}

distancia= 0.025 km

Por otro lado, aplicas la siguiente regla de tres: si 1 km es igual a 1,000 metros, ¿0.025 km cuántos metros son?

distancia=\frac{0.025 km*1,000 metros}{1 km}

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