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3 years ago

13

a cannon sits on a stationary railroad flatcar with a total mass of 1000 kg. when a 10 kg cannonball is fired to the left at a s

peed of 50 m/s, what is the speed of the flatcar

1 answer:

marishachu [46]3 years ago

6 0

Answer:

0.5 m/s

Explanation:

From Newton's Third law of motion,

Momentum of the cannon = momentum of the flatcar.

mv = MV........................ Equation 1

Where m = mass of the cannon, v = velocity of the cannon, M = mass of the flatcar, V = Velocity of the flat car.

make V the subject of the equation

V = mv/M................... Equation 2

Given: m = 10 kg, v = 50 m/s, M = 1000 kg

Substitute into equation 2

V = 10×50/1000

V = 500/1000

V = 0.5 m/s

Hence the speed of the flatcar = 0.5 m/s

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Answer:

Height = 53.361 m

Explanation:

There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12

From the given information we make the following summary

$u_{1}$ = 0m/s

$t_{1}$ = t

$u_{2}$ = 43.12m/s

$t_{2}$ = (t-2.2)s

The distance by the first balloon is

$D = u_{1} t_{1} + \frac{1}{2} at_{1}^2$

where

a = 9.8m/s2

Inputting the values

$D = (0)t + \frac{1}{2} (9.8)t^2\\ D = 4.9t^2$

The distance traveled by the second balloon

$D = u_{2} t_{2} + \frac{1}{2} at_{2}^2$

Inputting the values

$D = (43.12)(t-2.2) + \frac{1}{2} (9.8)(t-2.2)^2$

simplifying

$D = 4.9t^2 + 21.56t -71.148$

Substituting D of the first balloon into the D of the second balloon and solving

$4.9t^2 = 4.9t^2 + 21.56t -71.148 \\ 21.56t = 71.148\\ t = 3.3s$

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

$D = 4.9(3.3)^2\\ D = 53.361 m$

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3 years ago

There is friction between the block and the

Norma-Jean [14]

Answer:

5 no

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actually the 4kg lying on table has no influence

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A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an

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Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

mass × g = k × length

put here value and find k

k = $\frac{5*9.8}{.01}$

k = 490 N/m

and ω is

ω = $\sqrt{\frac{k}{m} }$

ω = $\sqrt{\frac{490}{5} }$

ω = 9.9

so here position w.r.t time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

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Nucleus P decays in two stages to produce nucleus Q. which decay sequence will result in the highest number of neutrons in nucle

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A beta particle followed by another beta particle. Consider it beta positive decay in which a proton decays to form a neutron,positron and electron neutrino.

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A roller coaster has a "hump" and a "loop" for riders to enjoy (see picture). The top of the hump has a radius of curvature of 1

nikklg [1K]

Answer:

Part a)

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Part B)

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Explanation:

Part A)

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Part B)

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$F_n + mg = \frac{mv^2}{R}$

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$v = \sqrt{15\times 9.81}$

$v = 12.1 m/s$

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3 years ago