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nadya68 [22]
3 years ago
6

Give reason Pascal is a derived unit​

Physics
1 answer:
Stells [14]3 years ago
4 0

Answer:

Pascal is a derived unit because <u>it</u><u> </u><u>cannot</u><u> </u><u>be</u><u> </u><u>expressed</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>physics</u><u> </u><u>terms</u><u>,</u><u> </u><u>but</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>an</u><u> </u><u>expression</u><u> </u><u>of</u><u> </u><u>fundamental</u><u> </u><u>quantities</u><u>.</u>

Explanation:

{ \sf{Pasacal \: ( Pa) =  \frac{newtons}{metres {}^{2} } }} \\  \\ { \sf{Pasacal  \: (Pa) =  \frac{kg \times  {ms}^{ - 2} }{ {m}^{2} } }}

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A baseball is thrown at an angle of 20° relative to the ground at a speed of 25 m/s if the ball was caught 50 m from the thrower
scoray [572]

Answer:

2.1 s

Explanation:

The motion of the ball is a projectile motion. We know that the horizontal range of the ball is

d = 50 m

And that the initial speed of the ball is

u=25 m/s

at an angle of

\theta=20^{\circ}

So, the horizontal speed of the ball (which is constant during the entire motion) is

u_x = u cos \theta = 25 \cdot cos 20^{\circ} = 23.5 m/s

And since the horizontal range is 50 m, the time taken for the ball to cover this distance was

t=\frac{d}{u_x}=\frac{50}{23.5}=2.1 s

which is the time the ball spent in air.

8 0
3 years ago
Which statement describes a chemical property related to the particles that make up the material
Stells [14]

Answer: The correct answer would be C.  Salt crystals are hard and brittle because they are made up of atoms that combine by ionic bonding.

Explanation: All the other ones are chemical changes because a new substance is formed.

7 0
3 years ago
The velocity of waves having wavelength 0.643 m and frequency 3.25 e 10 hz is
Alexeev081 [22]

The relationship between velocity (v), wavelength (w) and frequency (f) is expressed as:

v = w f

Plugging in the given values into the equation:

v = 0.643 m (3.25 e 10 Hz)

Where Hz = 1 / s , therefore:

v = 0.643 m (3.25 e 10 / s)

v = 2.09 <span>e 10 m / s</span>

4 0
4 years ago
Which type of friction prevents a pile of rocks from falling apart?
andrew11 [14]
Static friction because the rocks arent moving are they?
3 0
3 years ago
Read 2 more answers
A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache
Paladinen [302]

Answer:

F_a=1470\ N

Explanation:

<u>Friction Force</u>

When objects are in contact with other objects or rough surfaces, the friction forces appear when we try to move them with respect to each other. The friction forces always have a direction opposite to the intended motion, i.e. if the object is pushed to the right, the friction force is exerted to the left.

There are two blocks, one of 400 kg on a horizontal surface and other of 100 kg on top of it tied to a vertical wall by a string. If we try to push the first block, it will not move freely, because two friction forces appear: one exerted by the surface and the other exerted by the contact between both blocks. Let's call them Fr1 and Fr2 respectively. The block 2 is attached to the wall by a string, so it won't simply move with the block 1.  

Please find the free body diagrams in the figure provided below.

The equilibrium condition for the mass 1 is

\displaystyle F_a-F_{r1}-F_{r2}=m.a=0

The mass m1 is being pushed by the force Fa so that slipping with the mass m2 barely occurs, thus the system is not moving, and a=0. Solving for Fa

\displaystyle F_a=F_{r1}+F_{r2}.....[1]

The mass 2 is tried to be pushed to the right by the friction force Fr2 between them, but the string keeps it fixed in position with the tension T. The equation in the horizontal axis is

\displaystyle F_{r2}-T=0

The friction forces are computed by

\displaystyle F_{r2}=\mu \ N_2=\mu\ m_2\ g

\displaystyle F_{r1}=\mu \ N_1=\mu(m_1+m_2)g

Recall N1 is the reaction of the surface on mass m1 which holds a total mass of m1+m2.

Replacing in [1]

\displaystyle F_{a}=\mu \ m_2\ g\ +\mu(m_1+m_2)g

Simplifying

\displaystyle F_{a}=\mu \ g(m_1+2\ m_2)

Plugging in the values

\displaystyle F_{a}=0.25(9.8)[400+2(100)]

\boxed{F_a=1470\ N}

8 0
3 years ago
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