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kondaur [170]
3 years ago
9

Calculate H3O+ when OH- is 2*10 -8

Chemistry
1 answer:
klio [65]3 years ago
6 0
Relationship between [H3O+] and [OH-] is:

[H3O+] X [OH-] = 1.00 X10^-14

Rearranging gives:
[H3O+] = 1.0X10^-14 / [OH-]

Just plug in and calculate your [H3O+] values
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