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kondaur [170]
3 years ago
9

Calculate H3O+ when OH- is 2*10 -8

Chemistry
1 answer:
klio [65]3 years ago
6 0
Relationship between [H3O+] and [OH-] is:

[H3O+] X [OH-] = 1.00 X10^-14

Rearranging gives:
[H3O+] = 1.0X10^-14 / [OH-]

Just plug in and calculate your [H3O+] values
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If an object is suspended in a fluid, neither sinking nor floating, then:
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Please help!!<br> I don’t understand
laiz [17]
<h3>Answer:</h3>

150 g Si

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Use Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.2 × 10²⁴ atoms Si

[Solve] grams Si

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Si - 28.09 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.2 \cdot 10^{24} \ atoms \ Si(\frac{1 \ mol \ Si}{6.022 \cdot 10^{23} \ atoms \ Si})(\frac{28.09 \ g \ Si}{1 \ mol \ Si})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 149.266 \ g \ Si

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. Instructed to round to 2 sig figs.</em>

149.266 g Si ≈ 150 g Si

4 0
3 years ago
Someone can help me with the question 3, please
pav-90 [236]
Answer ————
60.8 g ammonia
5 0
3 years ago
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