The mass of sodium sulfite that was used will be 1,890 grams.
<h3>Stoichiometric problems</h3>First, the equation of the reaction:
The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.
Mole of 960 grams SO2 = 960/64 = 15 moles
Equivalent mole of sodium sulfite that reacted = 15 moles
Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams
More on stoichiometric problems can be found here: brainly.com/question/14465605
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The percent by mass of 110.6 g of potassium fluoride (NaF) dissolved in 1500.0 g of water is 0.073733 %.
<h3>What is the mass percentage?</h3>The mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.
Calculate the mass percent of potassium fluoride, using the formula:
Mass percentage = 0.073733 %
Hence, the percent by mass of 110.6 g of potassium fluoride (NaF) dissolved in 1500.0 g of water is 0.073733 %.
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