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marissa [1.9K]
3 years ago
6

10. Inertia causes your books on the car seat to continue moving forward even after you brake. TrueFalse 11. Tires with little o

r no tread do not have good traction on a wet, snowy, or icy road. TrueFalse 12. When driving on ice and snow, traction is poorest when the temperature is near 32 degrees F. TrueFalse 13. The more energy of motion that a car has, the less time and distance it will take to stop. TrueFalse 14. To help slow a car using engine braking, just take your foot off the accelerator. TrueFalse
Physics
1 answer:
Charra [1.4K]3 years ago
3 0

10. True

11. True

12. True

13. False

14. False

Hope this helps!!

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A uniformly charged sphere has a potential on its surface of 450 V. At a radial distance of 7.2 m from this surface, the potenti
Yakvenalex [24]

Answer:

The radius of the sphere is 3.6 m.

Explanation:

Given that,

Potential of first sphere = 450 V

Radial distance = 7.2 m

If the potential of sphere =150 V

We need to calculate the radius

Using formula for potential

For 450 V

V=\dfrac{kQ}{r}

450=\dfrac{kQ}{r}....(I)

For 150 V

150=\dfrac{kQ}{r+7.2}....(II)

Divided equation (I) by equation (II)

\dfrac{450}{150}=\dfrac{\dfrac{kQ}{r}}{\dfrac{kQ}{r+7.2}}

3=\dfrac{(r+7.2)}{r}

3r=r+7.2

r=\dfrac{7.2}{2}

r=3.6\ m

Hence, The radius of the sphere is 3.6 m.

3 0
3 years ago
15m/s is how many Newtons
GuDViN [60]
147.09975 newton meters per second
5 0
3 years ago
What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE ar
Papessa [141]

Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

M = mass of the planet

r = radius of the planet

From the question, we got that the mass of the planet is

M = 9ME, where ME = 5.95*10^24

M = 9 * 5.95*10^24

M = 5.355*10^25 kg

Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

R = 3 * 6.37*10^6

R = 1.911*10^7 m

On applying the values of both R and M to the equation, we get

g = GM/r²

g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²

g = 3.57*10^15/3.65*10^14

g = 9.78 m/s²

Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

Please vote brainliest if it helped you <3

5 0
3 years ago
When the Moon orbits Earth, what is the centripetal force?
Troyanec [42]

Answer:

D

Explanation:

pls mark brainliest

7 0
3 years ago
8.
Arisa [49]

Answer:

can you translate that plz

Explanation:

5 0
3 years ago
Read 2 more answers
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