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natulia [17]
4 years ago
12

Which gas is a source of natural groundwater pollution?

Physics
1 answer:
Hatshy [7]4 years ago
7 0
It is A) Radon Gas! :D

 Radon gas is a contaminated stock of the oxidation of spontaneously befalling uranium within the Earth's shell.

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A block lies on a horizontal frictionless surface and
zhenek [66]

Answer:

0.1 m

Explanation:

F = Force exerted on spring = 3 N

k = Spring constant = 60 N/m

x = Displacement of the block

As the energy of the system is conserved we have

Fx=\dfrac{1}{2}kx^2

\\\Rightarrow x=\dfrac{2F}{k}

\\\Rightarrow x=\dfrac{2\times 3}{60}

\\\Rightarrow x=0.1\ m

The position of the block is 0.1 from the initial position.

6 0
3 years ago
Plzzz help will give brainlist
zhenek [66]

Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

5 0
3 years ago
When a gas is cooled, the particles begin to move more______(Quickly/slowly). When the temperature drops below the____ (melting
bija089 [108]
Slowly; Boiling Point; Decrease; Decrease; Vibrate in place.

As temperature drops, so does thermal energy, and particle motion drops. The same trends in temperature, thermal energy, and motion applys to phases in decreasing order: gas>liquid>solid. The particle motion is always vibrations in place for solids because they are very tightly packed compared to liquids and gases.
6 0
4 years ago
A hard drive has 250 gigabytes of storage?
Dafna11 [192]
A. 0.25 terabytes
b. 2.5e + 17
4 0
3 years ago
When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic
alexandr1967 [171]

Coefficient of volume expansion is 8.1 ×10⁻⁴ C⁻¹.

<u>Explanation:</u>

The volume expansion of a liquid is given by ΔV,

ΔV = α V₀ ΔT

ΔT = change in temperature  = 48.5° C

α =  coefficient of volume expansion =?

V₀ = initial volume = 2.35 m³

We need to find α , by plugin the given values in the equation and by rearranging the equation as,

\alpha=\frac{\Delta \mathrm{V}}{\mathrm{V}_{0} \Delta \mathrm{T}}=\frac{0.0920}{2.35 \times 48.5}=0.00081

  = 8.1 ×10⁻⁴ C⁻¹.

5 0
3 years ago
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