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IRINA_888 [86]
4 years ago
6

Brain surgery. Surgeons can remove brain tumors by using a cavitron ultrasonic surgical aspirator, which produces sound waves of

frequency 23.0 kHzkHz . What is the wavelength of these waves in air
Physics
1 answer:
dmitriy555 [2]4 years ago
7 0

Answer:\lambda =1.304\times 10^4\ m

Explanation:

Given

frequency of wave \nu =23\ kHz

We know velocity is given by

v=\nu \times \lambda

where \lambda=wavelength

\lambda =\frac{velocity}{\nu }

\lambda =\frac{3\times 10^8}{23\times 10^3}

\lambda =1.304\times 10^4\ m

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An airplane traveling from Atlanta to New York travels 1,395 km in 2.5 h. What is the plane’s average speed?
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D. 558 km/h because if you divide 1,395 by 2.5 you’ll get the answer and I know this is correct because the keyword for me to divide is average.
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When forming a bond, an atom that has 3 electrons in its second shell and a filled first shell will?
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3 years ago
Which formula is used to calculate average velocity?
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7 0
3 years ago
Read 2 more answers
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
3 years ago
To start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 57.0° above the ho
cupoosta [38]

Answer:

xf = 5.68 × 10³ m  

yf = 8.57 × 10³ m  

Explanation:

given data

vi = 290 m/s

θ = 57.0°

t = 36.0 s

solution

firsa we get here origin (0,0) to where the shell is launched

xi = 0                            yi = 0

xf = ?                            yf = ?

vxi =  vicosθ               vyi = visinθ  

ax = 0                          ay = −9.8 m/s

now we solve x motion: that is

xf = xi + vxi × t + 0.5 × ax × t²     ............1

simplfy it we get

xf = 0 + vicosθ × t + 0

put here value and we get

xf = 0 + (290 m/s) cos(57) (36.0 s)

xf = 5.68 × 10³ m  

and

now we solve for y motion: that is

yf = yi + vyi × t + 0.5 × ay × t ²     ............2

put here value and we get

yf = 0 + (290 m/s) × sin(57) × (36.0 s) + 0.5 × (−9.8 m/s2) × (36.0 s)  ²

yf = 8.57 × 10³ m  

5 0
4 years ago
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