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3 years ago

6

Brain surgery. Surgeons can remove brain tumors by using a cavitron ultrasonic surgical aspirator, which produces sound waves of

frequency 23.0 kHzkHz . What is the wavelength of these waves in air

1 answer:

dmitriy555 [2]3 years ago

7 0

Answer: $\lambda =1.304\times 10^4\ m$

Explanation:

Given

frequency of wave $\nu =23\ kHz$

We know velocity is given by

$v=\nu \times \lambda$

where $\lambda$ =wavelength

$\lambda =\frac{velocity}{\nu }$

$\lambda =\frac{3\times 10^8}{23\times 10^3}$

$\lambda =1.304\times 10^4\ m$

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I have a test for my finals can y’all help me?

drek231 [11]

What’s the question? I may be able to help

7 0

3 years ago

A 21.6−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h

IrinaK [193]

Answer : The specific heat capacity of the alloy $1.422J/g^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$C_1$ = specific heat of alloy = ?

$C_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of alloy = 21.6 g

$m_2$ = mass of water = 50.0 g

$T_f$ = final temperature of system = $31.10^oC$

$T_1$ = initial temperature of alloy = $93.00^oC$

$T_2$ = initial temperature of water = $22.00^oC$

Now put all the given values in the above formula, we get

$21.6g\times c_1\times (31.10-93.00)^oC=-50.0g\times 4.18J/g^oC\times (31.10-22.00)^oC$

$c_1=1.422J/g^oC$

Therefore, the specific heat capacity of the alloy $1.422J/g^oC$

6 0

3 years ago

What radiation do remote controls use?

aleksandr82 [10.1K]

Answer:infrared radiation

Explanation:

Most remote control uses infrared radiation

5 0

3 years ago

An aquifer pump test was conducted in a confined aquifer where the initial piezometric surface was at elevation 12.45 m, and wel

murzikaleks [220]

Answer:

T = 0.0088 m²/s

Explanation:

given,

initial piezometric elevation = 12.5 m

thickness of aquifer = 14 m

discharge = 28.24 L/s = 0.02824 m³/s

we know

$k = \dfrac{qln(\dfrac{R_2}{R_1})}{2\pi D(H_2-H_1)}$

$k = \dfrac{0.02824 \times ln(\dfrac{75}{25})}{2\pi \times 14 (11.45-10.89)}$

k = 0.629 mm/sec

Transmissibilty

T = k × H

T = 0.629 × 14 × 10⁻³

T = 0.0088 m²/s

4 0

3 years ago

While playing a scavenger hunt game, Anthony walks 48.0 m to the south and then walks 12.0 m to the west. What single straight-l

Alenkasestr [34]

As these are distances created by moving in a straight line, using a trigonometric analysis can solve the missing single straight-line displacement. Looking at the 48m and 12m movements as legs of a triangle, obtaining the hypotenuse using the pythagorean theorem will yield us the correct answer.
This is shown below:

c^2 = 48^2 + 12^2
c = sqrt(2304 + 144)
c = sqrt(2448)
c = 49.48 m

To obtain the angle at which Anthony walks 49.48, we obtain the arc tangent of (12/48). This is shown below:

arc tan (12/48) =14.04 degrees.

Therefore, Anthony could have walked 49.48 m towards the S 14.04 W direction.

4 0

3 years ago